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ladessa [460]
3 years ago
5

47526 to the nearest 10​

Chemistry
1 answer:
german3 years ago
5 0

Answer:

47530 is the nearest 10 to 47526

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Specific gravity is a number representing the ratio of a mineral's weight to the weight of an equal volume of water. TRUE FALSE
777dan777 [17]

Answer: True

Explanation: Specific Gravity of a body, also called its Relative Density, is the ratio of the density of that body to the density of a reference material (usually water).

With the Mathematics done right, it is evident that the specific gravity of a body would be equal to the ratio of mass/weight of the body to the mass/weight of an equal volume of water.

S.G = (Density of body)/(Density of water)

Density of Body = (mass/weight of body)/(volume of body)

Density of water = (mass/weight of water)/(volume of water)

If volume of Body = Volume of water, then,

S.G = (Mass/Weight of body)/(Mass/Weight of equal volume of water)

Proved!!

3 0
3 years ago
Indicate how you might prepare acetic acid from ethene
ruslelena [56]
Acetic acid can be prepared from ethane by oxidizing it. Acetic acid is generally a carboxylic acid. These acids can be made by the oxidation of alcohols using potassium dichromate(VI) solution with sulfuric acid. Ethane is made into acetic acid in two steps. First it is formed into an aldehyde and then to acetic acid.
8 0
2 years ago
Calculate the acid dissociation constant Ka of a 0.2 M solution of weak acid that is 0.1% ionized is ________.
mars1129 [50]

Answer: acid dissociation constant Ka= 2.00×10^-7

Explanation:

For the reaction

HA + H20. ----> H3O+ A-

Initially: C. 0. 0

After : C-Cx. Cx. Cx

Ka= [H3O+][A-]/[HA]

Ka= Cx × Cx/C-Cx

Ka= C²X²/C(1-x)

Ka= Cx²/1-x

Where x is degree of dissociation = 0.1% = 0.001 and c is the concentration =0.2

Ka= 0.2(0.001²)/(1-0.001)

Ka= 2.00×10^-7

Therefore the dissociation constant is

2.00×10^-7

7 0
2 years ago
Theory is often used as a synonym for idea in everyday life.
Rasek [7]
I think B. As an idea is just a way that could be possible
8 0
3 years ago
By pipet, 11.00 mL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask
tangare [24]

Answer:

1) 0.18106 M is the molarity of the resulting solution.

2) 0.823 Molar is the molarity of the solution.

Explanation:

1) Volume of stock solution = V_1=11.00 mL

Concentration of stock solution = M_1=0.823 M

Volume of stock solution after dilution = V_2=50.00 mL

Concentration of stock solution after dilution = M_2=?

M_1V_1=M_2V_2 ( dilution )

M_2=\frac{0.823 M\times 11.00 mL}{50 ,00 mL}=0.18106 M

0.18106 M is the molarity of the resulting solution.

2)

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of potassium permanganate = 13.0 g

Molar mass of potassium permangante = 158 g/mol

Volume of the solution = 100.00 mL = 0.100  L ( 1 mL=0.001 L)

Molarity=\frac{13.0 g}{158 g/mol\times 0.100 L}=0.823 mol/L

0.823 Molar is the molarity of the solution.

6 0
2 years ago
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