Answer:
(a) from the anode to the cathode through the external circuit
Explanation:
In an electrochemical cell, there are two half cells; the oxidation half cell and reduction half cell. Oxidation typically refers to loss of electrons and reduction refers to gain of electrons.
Electrons always flow from the anode to the cathode or from the oxidation half cell to the reduction half cell.
The electrical circuit in an electrochemical cell confirms the flow of electron. Usually a light bulb is attached. The correct option is;
(a) from the anode to the cathode through the external circuit
It is false :D I am 95% sure
Explanation:
Formula to calculate hybridization is as follows.
Hybridization =
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
So, hybridization of
is as follows.
Hybridization =
=
= 2
Hybridization of
is sp. Therefore,
is a linear molecule. There will be only two electron groups through which Be is attached.
Similarly, hybridization of
is calculated as follows.
Hybridization =
=
= 5
Therefore, hybridization of
is
is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.
Thus, we can conclude that out of the given options
is the correct examples of linear molecules for five electron groups.
molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)
molar mass = 84.01 g/mol
//
(508g)(1 mol/84.01 g) = 6.0
There are 6.0 moles of sodium bicarbonate