What does 3 dots inside a silver ring mean?

Chemistry

2 answers:

Alex73 [517]3 years ago

8 0

It's reported inside the riddles or decorations

frez [133]3 years ago

3 0

There is really no way of knowing unless the particular 'maker' of the ring is reknown. I would suggest to take it to a jeweler to have it tested to see if it is real gold or gold platitum mixed etc. Most reliable jewelry stores will test it free, especially if you tell them, 'If this is real, I'm thinking about hiring you to polish it.; This is what I did the last time I found a gold/diamond ring, and after finding out it was the real deal, I paid them $25.00 to polish it, and it looks brand new.

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Which is bigger 145 m or 145 km

Citrus2011 [14]

145 km i think is bigger

8 0

3 years ago

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You have 0.5 L of air at 203 k in an expendable container at constant pressure. You heat the container to 273 k. What is the vol

avanturin [10]

Charles law states that for a fixed mass of gas at constant pressure the volume of the gas is directly proportional to the temperature in Kelvin scale

v1/T1 = v2/T2

Where v1 is volume and T1 is temperature at the first instance

v2 is volume and T2 is temperature at the second instance

Substituting the values in the equation

0.5 L / 203 K = v2 / 273 K

v2 = 0.672 L

The volume of Air after heating is 0.672 L

6 0

2 years ago

In the reaction of 675.9 grams of barium chloride and excess silver(I) nitrate, how many grams of silver(I) chloride should get

zvonat [6]

Taking into account the reaction stoichiometry, the mass of silver(I) chloride formed is 930.37 grams.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + BaCl₂ → 2 AgCl + Ba(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgNO₃: 2 moles
BaCl₂: 1 mole
AgCl: 2 moles
Ba(NO₃)₂: 1 mole

The molar mass of the compounds is:

AgNO₃: 169.87 g/mole
BaCl₂: 208.24 g/mole
AgCl: 143.32 g/mole
Ba(NO₃)₂: 261.34 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgNO₃: 2 moles ×169.87 g/mole= 339.74 grams

BaCl₂: 1 mole ×208.24 g/mole= 208.24 grams

AgCl: 2 moles ×143.32 g/mole= 286.64 grams

Ba(NO₃)₂: 1 mole×261.34 g/mole= 261.34 grams

<h3>Mass of silver(I) chloride formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 208.24 grams of barium chloride form 286.64 grams of silver(I) chloride, 675.9 grams of barium chloride form how much mass of silver(I) chloride?

$mass of silver(I) chloride=\frac{675.9 grams of barium chloride x286.64 grams of silver(I) chloride }{208.24 grams of barium chloride}$