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Elan Coil [88]
3 years ago
14

What is formed from joining positive and negative ions

Chemistry
1 answer:
dsp733 years ago
4 0
I think it’s an ionic bond
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1‑Propanol ( P⁰ 1 = 20.9 Torr at 25 ⁰C ) and 2‑propanol ( P⁰ 2 = 45.2 Torr at 25 ⁰C ) form ideal solutions in all proportions. L
anastassius [24]

Answer : The mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

Explanation : Given,

Vapor presume of 1‑Propanol (P^o_1) = 20.9 torr

Vapor presume of 2‑Propanol (P^o_2) = 45.2 torr

Mole fraction of 1‑Propanol (x_1) = 0.540

Mole fraction of 2‑Propanol (x_2) = 1-0.540 = 0.46

First we have to calculate the partial pressure of 1‑Propanol and 2‑Propanol.

p_1=x_1\times p^o_1

where,

p_1 = partial vapor pressure of 1‑Propanol

p^o_1 = vapor pressure of pure substance 1‑Propanol

x_1 = mole fraction of 1‑Propanol

p_1=(0.540)\times (20.9torr)=11.3torr

and,

p_2=x_2\times p^o_2

where,

p_2 = partial vapor pressure of 2‑Propanol

p^o_2 = vapor pressure of pure substance 2‑Propanol

x_2 = mole fraction of 2‑Propanol

p_2=(0.46)\times (45.2torr)=20.8torr

Thus, total pressure = 11.3 + 20.8 = 32.1 torr

Now we have to calculate the mole fraction of vapor phase 1‑Propanol and 2‑Propanol.

\text{Mole fraction of 1-Propanol}=\frac{\text{Partial pressure of 1-Propanol}}{\text{Total pressure}}=\frac{11.3}{32.1}=0.352

and,

\text{Mole fraction of 2-Propanol}=\frac{\text{Partial pressure of 2-Propanol}}{\text{Total pressure}}=\frac{20.8}{32.1}=0.648

Thus, the mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

3 0
3 years ago
Which of the following are considered pure substance??
Shkiper50 [21]

Answer:

Explanation:

I’m 99.9% sure that it’s an element because it can’t be broken down any more than it already is.

7 0
3 years ago
What does our state have that few share?
MissTica

Answer:

which state?

Explanation:

7 0
3 years ago
The rate constant for this second‑order reaction is 0.380 M − 1 ⋅ s − 1 0.380 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Sati [7]

Answer: 8.38 seconds

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

a_0 = initial concentartion = 0.860 M

a= concentration left after time t = 0.230 M

k = rate constant =0.380M^{-1}s^{-1}

\frac{1}{0.860}=0.380\times t+\frac{1}{0.230 }

t=8.38s

Thus it will take 8.38 seconds for the concentration of  A to decrease from 0.860 M to 0.230 M .

5 0
3 years ago
Which statement best explains why heating a liquid affects its velocity
nekit [7.7K]

Part of the answer you are looking for may be- Molecules overcome attractions easily and at high temperatures, move faster- (paraphrased from Google) Since the question asked was not provided with the statements as proposed in the original question, I cannot give you an exact answer. I did what i could do, hope this helps!

3 0
3 years ago
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