Answer:
The correct question is:
"Find the energy each gains"
The energy gained by a charged particle accelerated through a potential difference is given by
![\Delta U = q\Delta V](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20q%5CDelta%20V)
where
q is the charge of the particle
is the potential difference
For a proton,
![q=+e=1.6\cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D%2Be%3D1.6%5Ccdot%2010%5E%7B-19%7DC)
And since ![\Delta V=100 V](https://tex.z-dn.net/?f=%5CDelta%20V%3D100%20V)
The energy gained by the proton is
![\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J](https://tex.z-dn.net/?f=%5CDelta%20U%3D%281.6%5Ccdot%2010%5E%7B-19%7D%29%28100%29%3D1.6%5Ccdot%2010%5E%7B-17%7DJ)
For an alpha particle,
![q=+2e=3.2\cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D%2B2e%3D3.2%5Ccdot%2010%5E%7B-19%7DC)
Therefore, the energy gained is
![\Delta U=(3.2\cdot 10^{-19})(100)=3.2\cdot 10^{-17}J](https://tex.z-dn.net/?f=%5CDelta%20U%3D%283.2%5Ccdot%2010%5E%7B-19%7D%29%28100%29%3D3.2%5Ccdot%2010%5E%7B-17%7DJ)
Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)
![q=+e=1.6\cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D%2Be%3D1.6%5Ccdot%2010%5E%7B-19%7DC)
So the energy gained is the same as the proton:
![\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J](https://tex.z-dn.net/?f=%5CDelta%20U%3D%281.6%5Ccdot%2010%5E%7B-19%7D%29%28100%29%3D1.6%5Ccdot%2010%5E%7B-17%7DJ)
Answer:
240N
Explanation:
The formula for force is F=mass×acceleration.
Therefore, Force= 120×2= 240N
![Power=\frac{Work}{Time}=\frac{Force\times distance}{time}](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7BWork%7D%7BTime%7D%3D%5Cfrac%7BForce%5Ctimes%20distance%7D%7Btime%7D)
If he wants to increase power, force must increase and decrease time.
Answer:
Some lenses are used to focus light to a pre-defined point based on the amount of curvature of their surfaces.
In a piano design convex, some surfaces are flat while others has positive lenses (biconvex)
Explanation:
Solution
These lenses are applied to pay attention to light in a point pre-defined based on the amount of curvature of their surfaces.
For that of a plano-convex design, one surface has a positive curve and for biconvex lenses, both surfaces are positively curved while the other remains flat.
when used practically, plano-convex lenses are most commonly used where the object being imaged is far apart from lens.
Part a)
Magnitude of electric field is given by force per unit charge
![E = \frac{F}{q}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BF%7D%7Bq%7D)
![E = \frac{4.3 * 10^{-6}}{2 * 10^{-9}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B4.3%20%2A%2010%5E%7B-6%7D%7D%7B2%20%2A%2010%5E%7B-9%7D%7D)
![E = 2150 N/C](https://tex.z-dn.net/?f=E%20%3D%202150%20N%2FC)
Part b)
Electrostatic force on the proton is given as
F = qE
![F = 1.6 * 10^{-19} * 2150](https://tex.z-dn.net/?f=F%20%3D%201.6%20%2A%2010%5E%7B-19%7D%20%2A%202150)
![F = 3.44 * 10^{-16} N](https://tex.z-dn.net/?f=F%20%3D%203.44%20%2A%2010%5E%7B-16%7D%20N)
PART C)
Gravitational force is given by
![F_g = mg](https://tex.z-dn.net/?f=F_g%20%3D%20mg)
![F_g = 1.6 * 10^{-27}*9.8](https://tex.z-dn.net/?f=F_g%20%3D%201.6%20%2A%2010%5E%7B-27%7D%2A9.8)
![F_g = 1.57 * 10^{-26} N](https://tex.z-dn.net/?f=F_g%20%3D%201.57%20%2A%2010%5E%7B-26%7D%20N)
PART d)
Ratio of electric force to weight
![\frac{F_e}{F_g} = \frac{3.44 * 10^{-16}}{1.57*10^{-26}}](https://tex.z-dn.net/?f=%5Cfrac%7BF_e%7D%7BF_g%7D%20%3D%20%5Cfrac%7B3.44%20%2A%2010%5E%7B-16%7D%7D%7B1.57%2A10%5E%7B-26%7D%7D)
![\frac{F_e}{F_g} = 2.2 * 10^{10}](https://tex.z-dn.net/?f=%5Cfrac%7BF_e%7D%7BF_g%7D%20%3D%202.2%20%2A%2010%5E%7B10%7D)