Which form of energy is involved in weighing fruit on a spring scale?
2 answers:
Answer:
d. gravitational potential energy and elastic potential energy
Explanation:
when fruits are weighed on the weighing scale using spring balance then the spring is stretched due to weight of the fruits
So here if the spring comes to rest just by stretching the spring by some amount of "x"
So here in that case we can say that the object will go down by same amount that is the amount of spring stretch
Now the gravitational potential energy of the spring will decrease as the height decreases and the same amount of spring potential energy will increase in that case.
So here we can say
loss in the gravitational potential energy = gain in the spring potential energy
You might be interested in
Answers:
a) 10 m
b) time=1.6 s, frquency=0.625 Hz
c) 6.25 m/s
Explanation:
a) If there is a crest at each dock and another three crests between the two docks, and the wavelength is the distance between to crests; this means we have
in
:
Clearing :
b) This part can be solved by a Rule of Three:
If 10 waves ---- 16 s
1 wave -----
Then:
This is the period of the wave
On the other hand, the frequency of the wave has an inverse relation with its period
:
This is the frequency of the wave
c) The speed of a wave is given by the following equation:
Finally:
Missing figure and missing details can be found here:
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
where k is the elastic constant of the spring and
is the stretch between the initial and final position. Since x1=-8 in=-0.203 m and x2=5 in=0.127 m, we have
(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
where the negative sign is given by the fact that
points in the opposite direction of the displacement of the cart, and where
therefore, the work done by the weight is
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
where k is the elastic constant of the spring and
(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
where the negative sign is given by the fact that
therefore, the work done by the weight is