1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ierofanga [76]
3 years ago
5

Which form of energy is involved in weighing fruit on a spring scale?

Physics
2 answers:
DanielleElmas [232]3 years ago
6 0

Answer:

d. gravitational potential energy and elastic potential energy

Explanation:

when fruits are weighed on the weighing scale using spring balance then the spring is stretched due to weight of the fruits

So here if the spring comes to rest just by stretching the spring by some amount of "x"

So here in that case we can say that the object will go down by same amount that is the amount of spring stretch

Now the gravitational potential energy of the spring will decrease as the height decreases and the same amount of spring potential energy will increase in that case.

So here we can say

mgx = \frac{1}{2}kx^2

loss in the gravitational potential energy = gain in the spring potential energy

ser-zykov [4K]3 years ago
3 0
There are two types of energies that are taking place in the fruit is weighed in a spring scale. These are the gravitational potential energy and the elastic potential energy. The gravitational potential energy could be primarily attributed to the elevation of the fruit with respect to the ground.
You might be interested in
How is the independent variable affected by the dependent variable
stiv31 [10]

Answer:

A dependent variable is a variable that is tested in an experiment. An independent variable is that can be modified. Depending on what you are testing, the dependent variable will change accordingly to the dependent variable.

- I'm reading this back and it doesn't make much sense, if you want me to reword this I can

5 0
3 years ago
Real springs have mass. How will the true period andfrequency
Ad libitum [116K]

Explanation:

An perfect mass less spring, attached at one end and with a free mass attached at the other end, will have a distinct frequency of oscillation depending on its constant spring and mass. On the other hand, a spring with mass along its length will not have a characteristic frequency of oscillation.

Alternatively, based on its spring constant and mass per length, it will now have a wave Speed. It would be possible to use all wavelengths and frequencies, as long as the component fλ= S, where S is the spring wave size. If that sounds like longitudinal waves, like solid sound waves.

4 0
3 years ago
Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor whe
spin [16.1K]
Average velocity =

      (displacement) / (time for the displacement)
and
      (direction of the displacement) .

Displacement =

      (distance from the start-point to the end-point)
and
      (direction from the start-point to the end-point)   .

When Ben is 200 meters from the corner store,
he is (500 - 200) = 300 meters from his house.

His displacement is

         300 meters in the direction
                             from his house to the neighbor .


His average velocity is

         (300/910) =  0.33 meters per second, in the
                               direction from his house to the neighbor .


7 0
3 years ago
Read 2 more answers
A rock is thrown off a 50.0 m high cliff. How fast must the rock leave the cliff top to land on level ground below, 90 m from th
blagie [28]

Answer:

The rock must leave the cliff at a velocity of 28.2 m/s

Explanation:

The position vector of the rock at a time t can be calculated using the following equation:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

r1 = (90 m, -50 m)

Then, using the equation of the vector position written above:

90 m = x0 + v0x · t

-50 m = y0 + 1/2 · g · t²

Since x0 and y0 = 0:

90 m = v0x · t

-50 m = 1/2 · g · t²

Let´s use the equation of the y-component of the vector r1 to find the time it takes the rock to reach the ground and with that time we can calculate v0x:

-50 m = 1/2 · g · t²

-50 m = -1/2 · 9.81 m/s² · t²

-50 m / -1/2 · 9.81 m/s² = t²

t = 3.19 s

Now, using the equation of the x-component of r1:

90 m = v0x · t

90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

v0x = 28.2 m/s

8 0
3 years ago
Why do racing cars have wider wheels?​
tamaranim1 [39]

Answer:

So they can last longer and have more grip than normal on-road cars. They need that in order for them to run well

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following correctly describes the formula for speed?
    11·2 answers
  • With which part of the brain is awareness typically associated?
    5·2 answers
  • a rectilinear motion of a particle is defined by v3=x3. determine the velocity and acceleration at x=8m
    11·1 answer
  • Which event causes the formation of trenches in Earth’s crust?
    6·2 answers
  • Why is your physical and mental health important?
    13·2 answers
  • How is newton's first law used in basketball?
    12·1 answer
  • Ten examples of non luminous objects​
    9·2 answers
  • The diagram shows a skydiver at different points of her jump. At what point would her
    15·1 answer
  • While in empty space, an astronaut throws a ball at a velocity of 9 m/s. What will the velocity of the ball be after it has trav
    14·1 answer
  • What is so fragile that just saying its name breaks it?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!