A watermelon cannon fires a watermelon vertically up into the air at a velocity of +9.5m/s, starting from an initial position of
1.2m above the ground. When the watermelon reaches the peak of its flight, what is:
a) the velocity _____
b) the acceleration _____
c) the elapsed time ______
d) the height above the ground _______
1 answer:
In 1 second the watermelon would be 10.7m above the ground. 2 seconds, 21.4m, 3 seconds,32.1m so on, so forth.
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