Answer:
a) 4NH₃ + 6NO ⇄ 6H₂O + 5N₂
b) 2H₂S + 3O₂ ⇄ 2H₂O + 2SO₂
Explanation:
Write the equation as given then modify accordingly.
a) NH3 + NO ⇄ H2O + N2
make sure that the amount of each element is equal in both side (reactants and products)
Hydrogen is the different one thus to make H egal we multiply by 2 in the reactant and by 3 in the product to make it 6. Thus the all reaction is multiply accordingly.
2NH3 + 3NO ⇄ 3H2O + 5/2N2
to remove the fraction, multiply both side by 2.
4NH3 + 6NO ⇄ 6H2O + 5N2
b) O2 + H2S ⇄ H2O + SO2
The Oxygen are not the same, so we make them equal to 6 in both side. in the reactant we have to multiply by 3. In the product we have to get 2 for water and 2 for SO2 to have a total of 6 O.
we modify the reaction accordingly to equal elements in both side.
2H2S + 3O2 ⇄ 2H2O + 2SO2
