Answer:
850g/min
Explanation:
The reaction expression is given as:
P₄ + 5O₂ → P₄O₁₀
Given that:
Number of moles of product = 1.5moles
Time = 30s = 0.5min
Unknown:
The rate of the reaction = ?
Solution:
Convert the moles given to mass of the product.
So;
Mass of product = number of moles x molar mass
Molar mass of P₄O₁₀ = 4(31) + 10(16) = 284g/mol
Mass of product = 1.5moles x 284g/mol = 426g
So;
Reaction rate = 
= 
= 850g/min
Question:
What would be the best way to increase the rate
of the reaction?
Answer:
D. She could make the original solutions at higher concentrations.
Answer:
Wet climates obviously have more water than driers climates. Metals, when subject to water have the tendency to oxidize rust. Therefore, if water is barely present in a climate, then oxidation is also least likely to occur.
Explanation:
Learnt it from reading a book
Answer:
- The molarity of the student's sodium hydroxide solution is 0.0219 M
Explanation:
<u>1) Chemical reaction.</u>
a) Kind of reaction: neutralization
b) General form: acid + base → salt + water
c) Word equation:
- sodium hydroxide + oxalic acid → sodium oxalate + water
d) Chemical equation:
- NaOH + H₂C₂O₄ → Na₂C₂O₄ + H₂O
b) Balanced chemical equation:
- 2NaOH + H₂C₂O₄ → Na₂C₂O₄ + 2H₂O
<u>2) Mole ratio</u>
- 2mol Na OH : 1 mol H₂C₂O₄ :1 mol Na₂C₂O₄ : 2 mol H₂O
<u>3) Starting amount of oxalic acid</u>
- mass = 28 mg = 0.028 g
- molar mass = 90.03 g/mol
- Convert mass in grams to number of moles, n:
n = mass in grams / molar mass = 0.028 g / 90.03 g/mol = 0.000311 mol
<u>4) Titration</u>
- Volume of base: 28.4 mL = 0.0248 liter
- Concentration of base: x (unknwon)
- Number of moles of acid: 2.52 mol (calculated above)
- Proportion using the theoretical mole ratio (2mol Na OH : 1 mol H₂C₂O₄)
That means that there are 0.000622 moles of NaOH (solute)
<u>5) Molarity of NaOH solution</u>
- M = n / V (liter) = 0.000622 mol / 0.0284 liter = 0.0219 M
That is the correct number using <em>three signficant figures</em>, such as the starting data are reported.
