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madam [21]
4 years ago
8

The C-14 decay is used to estimate the age of an old dead tree. The activity of C-14 in the dead tree is determined to have fall

en to 21% of its original value. C-14 has a half-life of 5700 years. Calculate, in years, the age of the dead tree.
I used the relevant formula but somehow my answer does not match with the markscheme. Can you help me?
Physics
1 answer:
meriva4 years ago
7 0
From the calculations i did, its 1197. Is that the one you got?
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Alex swims at an average speed of 45m/min. how far does he swim in 1 min 24 sec?
saveliy_v [14]

Answer:

63 m

Explanation:

Average speed of swimming = 45 m/min

Time = 1 minute 24 seconds

Converting time into minutes:

Formula:

Putting values, we get.

Thus, Alex swims for 63 m in 1 minute and 24 seconds.

6 0
3 years ago
If a person has the genotype Rr for hair where red is dominant to blue, what phenotype would this person have?
JulijaS [17]

the person's phenotype would be red hair. phenotype is what you see on the outside, genotype is what the dna says. <3

4 0
3 years ago
A variação no comprimento de uma barra de alumínio foi de 0,0002m. Calcular a variação na temperatura a =22x10-⁶
Furkat [3]

Answer:

1.82°C

Explanation:

presumir inicial comprimento = l₀ = 5 m

dado que:

coeficiente de expansão (α) = 22 x 10⁻⁶, A variação no comprimento (ΔL) = 0.0002 m,

inicial comprimento = l₀ = 5 m

variação na temperatura = ΔT

para Calcular a variação na temperatura,  nós usamos a fórmula:

\Delta L=l_0\alpha \Delta T

substituindo valores:

0.0002=5*22*10^{-6}\Delta T\\\Delta T=\frac{0.0002}{5*22*10^{-6}}\\ 5*22*10^{-6}=1.82^0C

variação na temperatura = 1.82°C

8 0
3 years ago
The energy of a photon is equal to (what) times (what) of the photon.
hjlf

The energy carried by a photon is equal to

(Planck's Konstant) times (the frequency of the photon) .

Planck's konstant is 6.626 x 10⁻³⁴ m²-kg/s  (rounded)

3 0
3 years ago
Read 2 more answers
A 6.00 g lead bullet traveling at420 m/s is stopped by a large
Westkost [7]

Answer:

The increase in temperature of the bullet is 351.1 kelvin

Explanation:

First, we should find the kinetic energy of the bullet is:

K=\frac{mv^{2}}{2}=\frac{(6\times10^{-3}\,kg)(420\,\frac{m}{s})^{2}}{2}

with m the mass and v the velocity.

K=529.2 J

Now we know that half of the kinetic energy of the bullet is transformed into internal energy, by second's law of thermodynamics that means heat (Q) to raise bullet temperature (T), so:

Q=\frac{K}{2}= 264.6\,J

To know what the increase in temperature is, we should use specific heat of lead:

c=125.604 \frac{J}{kg\.K}

The equation that relates specific heat, change in temperature and mass is:

Q=cm\varDelta T

solving for \varDelta T:

\varDelta T=\frac{Q}{cm}=\frac{264.6}{(125.604)(6\times10^{-3})}

\varDelta T= 351.10\, K

4 0
3 years ago
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