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4 years ago

You get in your car to drive to school at 7:33 am and drive 10 miles north at a constant speed until 7:45

Physics

1 answer:

ivann1987 [24]4 years ago

7 0

Answer:

5.) 16.8 m/s

6.) 16.1 mph

7.) Moving fast.

Explanation:

5.) From the question, the total time will be:

7:33 am to 7:45 am = 12 minutes

As the car turns around,

7 : 45 am to 8 : 00am = 15 minutes

As you get back in the car and drive 15

miles north to school at a constant speed arriving at school at 8:29 am

8:00am to 8:29 am = 29 minutes

Total time = 12 + 15 + 29 = 56 minutes

Convert the minutes to second by multiplying the result by 60

Total time = 56 × 60 = 3360 seconds

Total distance covered will be

10 miles + 10 miles + 15 miles = 35 miles

Convert mile to meter by multiplying the result by 1609.344

35 × 1609.344 = 56327.04

Speed is a scale quantity. It only involves magnitude but no direction.

Average speed = total distance/total time

Average speed = 56327.04/3360

Average speed = 16.764 m/s

6.) Velocity = displacement/time

Velocity is a vector quantity. We will consider both the magnitude and direction

Total displacement = 10 miles - 10 miles + 15 miles = 15 miles.

Total time = 56 minutes

Convert minutes to hours by dividing it by 60

Total time = 56/60 = 0.93 hours

Substitute the time and displacement into the formula

Velocity = 15/0.93 = 16.07 mph

7.) . If you looked at your speedometer on your drive to school and it read 30mph, this value describes you move with a fast speed.

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If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is

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Question:

The operations manager for a well-drilling company must recommend whether to build a new facility, expand his existing one, or do nothing. He estimates that long-run profits (in $000) will vary with the amount of precipitation (rainfall) as follows:

Alternative Precipitation

Low Normal High

Do nothing -100 100 300

Expand 350 500 200

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A. $140,000

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C. $285,000

D. $305,000

E. $475,000

Answer:

D. $170,000

Explanation:

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Low Normal High

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3 years ago

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o

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Answer:

B. 0.16 m

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$v_y = 0$

While the horizontal velocity is

$v_x = 15 m/s$

The horizontal distance covered is

$d_x = 2.7 m$

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

$t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s$

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$d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m$

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4 years ago