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3 years ago

8

Find the current passing through a circuit consisting of a battery and one resistor. The resistance has a retance of 2ohms and t

he battery hasa voltage of 12 volts

1 answer:

Bingel [31]3 years ago

5 0

The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere .

Explanation:

Assume the wires are ideal with zero resistance.

The current passing through the circuit will be

I = V/R = 12/2 = 6.000 A.

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Based on the data collected, explain why a launch angle of 30 degrees (HIGH HORIZONTAL VELOCITY & SMALL TIME OF FLIGHT) will

Gennadij [26K]

Answer:

Explanation:

The horizontal distance traveled by the projectile is given by the formula

$R=\frac{u^{2}Sin2\theta }{g}$

The formula for the time of flight is given by

$T = \frac{2u Sin\theta }{g}$

Case I: when the launch angle is 30°

So, $R_{1}=\frac{u^{2}Sin60 }{g}$

$R_{1}=\frac{0.866u^{2}}{g}$

Horizontal velocity = u Cos 30 = 0.866 u

$T_{1} = \frac{2u Sin30 }{g}=\frac{u}{g}$

Case II: when the launch angle is 60°

$R_{2}=\frac{u^{2}Sin120}{g}$

$R_{2}=\frac{0.866u^{2}}{g}$

Horizontal velocity = u Cos 60 = 0.5 u

$T_{1} = \frac{2u Sin60 }{g}=\frac{1.73 u}{g}$

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

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3 years ago

Light of wavelength 500 nm illuminates a round 0.50-mm diameter hole. A screen is placed 6.0 m behind the slit.. Find the width

Paul [167]

Answer:

15mm

Explanation:

We know that for circular holes first dark spot is given by

sin စ = 1.22 λ/D

Also we know that at the same time

tan စ = r/L

So

r = L tanစ = 6 x tan( arcsin(1.22x 500 x10^9/0.50 x 10^ 3))

= 0.0073 m = 7.3 mm

However since the size is twice that so 14.6 mm which is approx 15mm

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3 years ago

An object becomes positively charged when it

goldfiish [28.3K]

Answer:

A. loses an electron, it becomes positively charged.

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C

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