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3 years ago

If a ball is rolling across a floor at a constant speed is it accelerating

Physics

1 answer:

KATRIN_1 [288]3 years ago

8 0

You already told us that its speed is constant. That's one part of acceleration.

The other part of acceleration is the direction it's moving.

If it's rolling in a straight line, then there's no acceleration.

If it's curving left or right, then that's acceleration.

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22. On a day the wind is blowing toward the south at 3m/s, a runner jogs west at 4m/s. What is the velocity of the air relative

blagie [28]

The velocity of the air relative to the runner is 5 m/s.

<h3>What is the relative velocity?</h3>

We must recall that velocity is a vector quantity and the relative velocity must be obtained vectorially. Thus we know that;

Velocity of the runner = 4m/s. due west

Velocity of the wind = 3m/s due south

The relative velocity is;

Vr = √(4)^2 + (3)^2

Vr = 5 m/s

Learn more about relative velocity:brainly.com/question/20813206

#SPJ1

3 0

2 years ago

sasho [114]

As a liquid is heated, its vapor pressure increases until the vapor pressure equals the pressure of the gas above it. ... In order to form vapor, the molecules of the liquid must overcome the forces of attraction between them. The temperature of a boiling liquid remains constant, even when more heat is added.

6 0

3 years ago

A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9

Andreyy89

Answer:

$d = 0.0306 m$

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

$U + K = constant$

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

$\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0$

$7.05 + 30.5 = \frac{0.266}{r}$

$r = 7.08 \times 10^{-3} m$

so distance moved by the particle is given as

$d = r_1 - r_2$

$d = 0.0377 - 0.00708$

$d = 0.0306 m$

6 0

3 years ago

Which describes the image produced by the lens?

Shalnov [3]

Converging only; diverging lenses can only produce upright imageswhich are reduced in size; an inverted and magnified image can be produced by a converging lens when the object is located between F and 2F. also know as t-6 over 6 the science oligical sign

hope this helped

3 0

3 years ago

Read 2 more answers

The change in position is known as

Goryan [66]

Answer:

distance or displacement

Explanation:

the answer can be displacement or displacement. if the required measure is between two points, we can call it as distance. but if we are to find the distance moved, we call it displacement. though it sounds pretty similar, they are very different. displacement is the shortest distance of movement of a body to its final point (or to the asked point) and distance is the total distance travelled by the body. and while distance is a scalar quantity, that this value shows the magnitude, displacement is a vector quantity, that this value should show both magnitude and direction.

for example if an object travels from point A to point B that is a 10 meters away and back, the distance will be 10+10 which is 20 meters. but the displacement is 0!

since not much information is given, the answer can be both distance or displacement

4 0

4 years ago