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Eduardwww [97]
3 years ago
13

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is

EVPI (Expected value of Perfect Information)?
Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0

Question:

The operations manager for a well-drilling company must recommend whether to build a new facility, expand his existing one, or do nothing. He estimates that long-run profits (in $000) will vary with the amount of precipitation (rainfall) as follows:

Alternative             Precipitation                                

                        Low                Normal                 High

Do nothing    -100                       100                    300

Expand           350                       500                   200

Build new       750                       300                    0

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is EVPI (Expected value of Perfect Information)?

A. $140,000

B. $170,000

C. $285,000

D. $305,000

E. $475,000

Answer:

D. $170,000

Explanation:

The expected long run profits are  for

                        Low                Normal                 High

Do nothing    -100*0.3                100*0.2                   300*0.5 = 140

Expand           350*0.3                500*0.2                  200*0.5 = 305

Build new       750*0.3                300*0.2                  0*0.5    = 285

Therefore the expected long run profits are

$140,000

$305,000

$285,000

Based on his selected option being either to build new or to expand, the most profitable option is to expand

=$305,000

EVPI = EPPI-EMV =$170,000

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Answer:

a = 2.72 [m/s2]

Explanation:

To solve this problem we must use the following kinematics equation:

v_{f} =v_{o} + a*t

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t = time = 2 [min] = 2/60 = 0.0333 [h]

1200 = 25 + (a*0.0333)

a = 35250.35 [km/h2]

if we convert these units to units of meters per second squared

35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]

3 0
3 years ago
A physicist's right eye is presbyopic (i.e., farsighted). This eye can see clearly only beyond a distance of 97 cm, which makes
Ivan

Answer:

f = 19,877 cm   and  P = 5D

Explanation:

This is a lens focal length exercise, which must be solved with the optical constructor equation

        1 / f = 1 / p + 1 / q

where f is the focal length, p is the distance to the object and q is the distance to the image.

In this case the object is placed p = 25 cm from the eye, to be able to see it clearly the image must be at q = 97 cm from the eye

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the power of a lens is defined by the inverse of the focal length in meters

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For all turning vehicles, the rear wheels follow a ______ than the front wheels.
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For all turning vehicles, the rear wheels follow <u>Shorter path</u> than the front wheels.

Any turning vehicle, the rear(the back part of something, especially a vehicle.) wheels follow a shorter path than the front wheels. The longer the vehicle is, the greater the difference will be in path. Trucks initially swing out before making a turn

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Answer:

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v = 4.00 x 10³

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As we know,

⇒  F=m(\frac{\Delta v}{\Delta t} )

On substituting the given values, we get

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7 0
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Answer:

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6 0
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