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Ann [662]
2 years ago
15

2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is

Physics
2 answers:
olga2289 [7]2 years ago
7 0

Answer:

her displacement <em>s=337.5m</em>

Explanation:

check out the above attachment ☝️

Helga [31]2 years ago
6 0

Answer:

337.5 meters

Explanation:

Df = Do + vo t + 1/2 a t^2          Df= final displ     vo = original velocity

    =  0   +   0   + 1/2 (3)(15^2) = 337.5 meters

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ikadub [295]

I'm pretty sure that's what cameras do, or did, back when technology wasn't as advanced.

4 0
3 years ago
Which statement describes a surface wave?
Gekata [30.6K]

Answer: A surface wave is a wave that moves along the interface of two different materials, like air and water.

8 0
3 years ago
A professional boxer hits his opponent with a 1035 N horizontal blow that lasts 0.175 s. The opponent's total body mass is 120 k
12345 [234]

Answer:

(a) vf = 1.51 m/s

(b) vf = 36.22 m/s

Explanation:

The rate of change of momentum is equal to the force:

F = \frac{mv_f-mv_i}{t}

Ft = m(v_f-v_i)

where,

F = Force = 1035 N

t = time = 0.175 s

vi = initial speed = 0 m /s

vf = final speed = ?

(a)

m = mass of body = 120 kg

Therefore,

(1035\ N)(0.175\ s)=(120\ kg)(v_f - 0\ m/s)\\\\v_f = \frac{181.125\ Ns}{120\ kg} \\\\

<u>vf = 1.51 m/s</u>

<u></u>

(b)

m = mass of head = 5 kg

Therefore,

(1035\ N)(0.175\ s)=(5\ kg)(v_f - 0\ m/s)\\\\v_f = \frac{181.125\ Ns}{5\ kg} \\\\

<u>vf = 36.22 m/s</u>

7 0
3 years ago
A 2kg object is dropped from height of 10m. ignoring air resistance calculate:
lbvjy [14]

Answer:

ME= 196.2 J

KE= 136.2

Explanation:

potential energy=mgh 2*9.81*10

Our ME is quivalent to PE as that is the toal amount of energy in the system

Kinetic energy= 1/2 mv^{2}

to solve for kinetic enrgy we need to use a kinaetmtic equation that help us find velocity

vf= vi+at

but we need to find time first

d=vi+1/2(accelretaion)t^{2}

7=0+1/2(9.81)t^{2}

t= 1.19 s

vf= 0+ 9.81*1.19

vf= 11.67 m/s

Now

1/2 mv^{2}

1/2*2*11.67^{2}

= 136. 2

or we could just (PE/10)*7

so (196.2/10)*7

5 0
3 years ago
In an electric shaver, the blade moves back and forth over a distance of 2.00 mm. The motion is simple harmonic, with frequency
Jlenok [28]

Answer:

(A)  0.001 m  

(B) 0.75 m/s  

(C) 5.7 x 10^{2} m/s^{2}      

Explanation:

distance (d) = 2 mm

frequency (f) = 120 Hz

(A) amplitude (A) = half the distance moved by the blade

      amplitude = 2 / 2 = 1 mm = 0.001 m

(B) maximum blade speed (v) = ωA = 2πfA

     v = 2 x 3.14 x 120 x 0.001 = 0.75 m/s  

(c) maximum blade acceleration (a) = w^{2}A

     a = (2 x 3.14 x 120)^{2}x0.001 = 5.7 x 10^{2} m/s^{2}

5 0
3 years ago
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