Question

A 2mC charge traveling 10 m/s nears a wire carrying a 5 A current. If the charge's velocity and the wire's current are perpendicular when they are 1 cm apart, what is the magnetic force on the wire at that moment?

Answer 1

Answer:

The magnetic force on the wire at the moment is 2 micro-Newton/(Ampere-meter)

Explanation:

Formula for magnetic force is F = qvB*sin(theeta)

and B = μ*I / 2*pi*r

where

q = charge in coulomb

v = velocity

B = magnetic field strength

μ = permeability of free space

I = current

so from here we get B = (4*pi*10^(-7))(5) / 2*pi*0.01 = 0.0001-T

now ,

F = (2mC)*(10)*0.0001*sin(90)

F = 2 micro-Newton/(Ampere-meter)