This was due yesterday...
2 answers:
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Answer:
Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf
Explanation:
First we will find the acceleration of pickup truck.
As, the acceleration is uniform, therefore we can use Newton's third equation of motion:
2as =
First convert speed into ft/sec
1 mile/hr = 1.47 ft/sec
therefore,
37 mile/hr = 37 x 1.47 ft/sec
37 mile/hr = 54.39 ft/sec
with initial speed 0 ft/sec (starting from rest), using in equation of motion:
a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)
a = 6.88 ft/sec²
Now, the total shear force will be given by Newton's second law of motion:
F = ma
F = (460 lbm +72 lbm)(6.88 ft/sec²)
F = 3660 lbf
Now for the max shear force in each of the two pegs we divide total fore by 2:
Force in each peg = F/2 = (3660 lbf)/2
<u>Force in each peg = 1830 lbf</u>