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Kryger [21]
2 years ago
5

A truck moves as shown by

Physics
1 answer:
Irina-Kira [14]2 years ago
6 0

Answer:

Explanation:

a = Δv/Δt = (v₁ - v₀) / (t₁ - t₀)

A a = (10 - 0) / (5 - 0) = 2 m/s²

B a = (10 - 10) / (15 - 5) = 0 m/s²

C a = (5 - 10) / (25 - 15) = - 0.5 m/s²

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An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find
Valentin [98]

Answer:

Explanation:

An object in free fall, NOT experiencing parabolic motion, has an equation of

h(t)=\frac{1}{2} gt^2+h_0 which says:

The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.

For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;

g = 10 m/s/s, and

t = .5sec

5=\frac{1}{2}(-10)(.5)^2+h and

5 = -5(.5)² + h and

5 = -5(.25) + h and

5 = -1.25 + h so

h = 6.25

That's how high the window is above the ground.

8 0
3 years ago
A 2.13-kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 5.00 N
ANTONII [103]

Answer:

17.54N in -x direction.

Explanation:

Amplitude (A) = 3.54m

Force constant (k) = 5N/m

Mass (m) = 2.13kg

Angular frequency ω = √(k/m)

ω = √(5/2.13)

ω = 1.53 rad/s

The force acting on the object F(t) = ?

F(t) = -mAω²cos(ωt)

F(t) = -2.13 * 3.54 * (1.53)² * cos (1.53 * 3.50)

F(t) = -17.65 * cos (5.355)

F(t) = -17.57N

The force is 17.57 in -x direction

5 0
4 years ago
What are the strengths and limitations of the doppler and transit methods? What kind of planets are easiest to detect with each
Arturiano [62]

\huge\mathfrak\red{✔Answer:-}

Strength: able to detect planets in a wide range of orbits, as long as orbits aren't face on

Limitations: yield only planet's mass and orbital properties

3 0
3 years ago
How much distance does it take to stop a car going 30 m/s (67 mph) if the brakes can apply a force equal to one half the car’s w
denpristay [2]

Answer:

0

rqc3fgt9uwgtd.ojbxrfdgi8ubvg iohy

5 0
2 years ago
Can anybody help me please?
vovangra [49]

Answer:

1,2,5

Explanation:

7 0
3 years ago
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