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2 years ago

A truck moves as shown by

Physics

1 answer:

Irina-Kira [14]2 years ago

6 0

Answer:

Explanation:

a = Δv/Δt = (v₁ - v₀) / (t₁ - t₀)

A a = (10 - 0) / (5 - 0) = 2 m/s²

B a = (10 - 10) / (15 - 5) = 0 m/s²

C a = (5 - 10) / (25 - 15) = - 0.5 m/s²

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A car travel adistance of 45M in 35second What is the Speed of acar Give you answer in km/hr

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10km/hr or 80mph is the possible answer I can give

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3 years ago

Two diamonds begin a free fall from rest and from the same height 1 second apart.

Bumek [7]

Answer:

Explanation:

let t be time since the second diamond is released

a) y = ½g(t + 1)²

b) y' = ½g(t)²

25 = ½g(t + 1)² - ½gt²

25 = ½g(t² + 2t + 1) - ½gt²

25 = ½gt² + gt + ½g - ½gt²

25 = g(t + ½)

t + ½ = 25 / g

t = (25 / g) - ½

t = (25 / 9.8) - ½

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3 years ago

8. In the billiard ball room at the basement of Memorial Union, two identical balls are traveling toward each other along a stra

mel-nik [20]

Answer:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

Explanation:

In an elastic collision, both the total momentum and the total kinetic energy of the system are conserved.

The conservation of the momentum can be written as:

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where

$m_1$ is the mass of ball 1

$m_2$ is the mass of ball 2

$u_1$ is the initial velocity of ball 1

$u_2$ is the initial velocity of ball 2

$v_1$ is the final velocity of ball 1

$v_2$ is the final velocity of ball 2

The conservation of kinetic energy can be written as

$\frac{1}{2}m_1 u_2^2 + \frac{1}{2}m_2 u_2^2 = \frac{1}{2}m_1 v_1^2 + \frac{1}{2}m_2 v_2^2$

Working together the two equations, it is possible to find two expressions for the final velocities in terms of the initial velocities:

$v_1=\frac{m_1 -m_2}{m_1 +m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\v_2=\frac{2m_1}{m_1+m_2}u_1 -\frac{m_1 -m_2}{m_1 +m_2}u_2$

In this problem we have:

$m_1 = m_2 = m$ since the mass of the two balls is identical

$u_1=+4.67 m/s$ is the initial velocity of ball 1

$u_2=-7.89 m/s$ is the initial velocity of ball 2

Substituting into the equations, we find the final velocities:

$v_1=\frac{2m}{m+m}u_2=u_2 =-7.89 m/s\\v_2=\frac{2m}{m+m}u_1=u_1=+4.67 m/s$

Therefore:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

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3 years ago

Determine the kinetic energy of a 1000 kg roller coaster car that is moving with a speed of 20.0 m/s

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4 years ago

Read 2 more answers

1 Point

fenix001 [56]

Answer:

D. The friction force increases by 9600 N.

Explanation:

Frictional force is directly proportional to kinetic coefient of friction.

6 0

4 years ago