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Kryger [21]
2 years ago
5

A truck moves as shown by

Physics
1 answer:
Irina-Kira [14]2 years ago
6 0

Answer:

Explanation:

a = Δv/Δt = (v₁ - v₀) / (t₁ - t₀)

A a = (10 - 0) / (5 - 0) = 2 m/s²

B a = (10 - 10) / (15 - 5) = 0 m/s²

C a = (5 - 10) / (25 - 15) = - 0.5 m/s²

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Most interstellar clouds are: Most interstellar clouds are: much bigger than our solar system. similar in size to clouds in Eart
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Answer:

Most interstellar clouds are much bigger than our solar system.

Explanation:

An interstellar cloud  refers:

  • It is generally an accumulation of gas, plasma, and dust in our and other galaxies.
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Interstellar clouds can be large up to 106 solar masses

It is also often said to be the most massive entities in the galaxy.

Hence

we can say about Interstellar clouds,

They are much bigger than our solar system.

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2 years ago
What would happen if mass is continually added to a 1.4 solar mass neutron star?
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Eventually wouldn't it collapse in on itself and create black hole.
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Give a example of scalar quantity
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speed, volume, mass, temperature and power

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A constant power is supplied to a rotating disc .the relationship of angular velocity of disc and number of rotations made by th
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A rotating disc supplied with constant power where the relationship of the angular velocity of the disc and the number of rotations made by the disc is governed by Newton's second law for rotation. This law is specially made for rotating bodies which is extracted from Newton's second law of motion. 
6 0
3 years ago
Assuming a 8 kilogram bowling ball moving at 2 m/s bounces off a spring at the same speed that had before bouncing what is the a
Naya [18.7K]

a) 32 kg m/s

Assuming the spring is initially at rest, the total momentum of the system before the collision is given only by the momentum of the bowling ball:

p_i = m u = (8 kg)(2 m/s)=16 kg m/s

The ball bounces off at the same speed had before, but the new velocity has a negative sign (since the direction is opposite to the initial direction). So, the new momentum of the ball is:

p_{fB}=m v_b =(8 kg)(-2 m/s)=-16 kg m/s

The final momentum after the collision is the sum of the momenta of the ball and off the spring:

p_f = p_{fB}+p_{fS}

where p_{fS} is the momentum of the spring. For the conservation of momentum,

p_i = p_f\\p_i = p_{fB}+p_{fS}\\p_{fS}=p_i -p_{fB}=16 kg m/s -(-16 kg m/s)=32 kg m/s


b) -32 kg m/s

The change in momentum of bowling ball is given by the difference between its final momentum and initial momentum:

\Delta p=p_{fb}-p_i=-16 kg m/s - 16 kg m/s=-32 kg m/s


c) 64 N

The change in momentum is equal to the product between the average force and the time of the interaction:

\Delta p=F \Delta t

Since we know \Delta t=0.5 s, we can find the magnitude of the force:

F=\frac{\Delta p}{\Delta t}=\frac{-32 kg m/s}{0.5 s}=-64 N

The negative sign simply means that the direction of the force is opposite to the initial direction of the ball.


d) The force calculated in the previous step (64 N) is larger than the force of 32 N.

5 0
3 years ago
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