What volume of a 0.252 M hydroiodic acid solution is required to neutralize 18.0 mL of a 0.151 M barium hydroxide solution

Chemistry

1 answer:

zhenek [66]2 years ago

6 0

Answer: 10.8 M

Explanation:

$M_{A}V_{A}=M_{B}V_{B}\\(0.252)V_{A}=(18.0)(0.151)\\V_{A}=\frac{(18.0)(0.151)}{(0.252)} \approx \boxed{10.8 \text{ M}}$

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Read 2 more answers

The pH of 0.10 M solution of an acid is 6. What is the acid dissociation constant of the acid?

svlad2 [7]

Answer: Dissociation constant of the acid is $10^{-11}$ .

Explanation: Assuming the acid to be monoprotic, the reaction follows:

$HA\rightleftharpoons H^++A^-$

pH of the solution = 6

and we know that

$pH=-log([H^+])$

$[H^+]=antilog(-pH)$

$[H^+]=antilog(-6)=10^{-6}M$

As HA ionizes into its ions in 1 : 1 ratio, hence

$[H^+]=[A^-]=10^{-6}M$

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

$[HA]=[HA]-[H^+]$