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tiny-mole [99]
3 years ago
8

according to Newton's third law what is the equal and opposite force to the downward force of gravity pulling on a man standing

in the woods
Physics
2 answers:
Fudgin [204]3 years ago
7 0

When you're talking about gravity, it's easy to identify the equal
opposite forces.

Gravity ALWAYS produces an equal pair of opposite forces. 
They both act between the centers of the two objects, one in
each direction.

Consider the equal pair of opposite gravitational forces between
you and the Earth.  One force acts on you, and draws you toward
the center of the Earth.  We call that force "your weight". 
The other one acts on the Earth, and draws it toward the center
of you.  Hardly anybody ever talks about that one, but the two
forces are equal ... your weight on Earth is equal to the Earth's
weight on you !

RideAnS [48]3 years ago
3 0

Answer: it is the pulling upward exerted by the man on the Earth.

Explanation:

Newton's third law states that the forces come in pair: the action force and the reaction force.

Whenever an object (call it object 1) exerts a force (action force) on a second object (object 2), an equal in magnitude and opposite in direction force (reaction force) is exerted by the second object on the object 1.

Consider the force of gravity, which is the downward pulling exerted by Earth on the man standing in the woods, the action force, then the reaction force, is the counteracting force exerted by the man on the Earth, and it is a pulling of the same magnitude of the gravity pulling but upward. The downward pulling is exerted on the man, but the upward pulling is exerted on the Earth.

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<em>Glad to help ya!! ;)</em>

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A top of rotational inertia 4.0 kg m2 receives a torque of 2.4 nm from a physics professor. the angular acceleration of the body
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3 years ago
The body weighing 2 kg moves through the horizontal surface and crosses the path x = 75 cm The coefficient of friction of the bo
Taya2010 [7]

The kinetic energy of the body in definitive position is 4.24 J.

Explanation:

As per the work energy theorem, the work done on any system or object to move it from one position to another is equal to the change in kinetic energy of the object. In this case, the body weighing 2 kg is moved over an horizontal surface for a distance of 75 cm. As there will be frictional force acting on the body while moving over the surface. This frictional force multiplied by the distance the object is moved will give the work done on the body.

Frictional force = Coeffficent of friction × Normal force.

As the weight of the body is 2 kg, the normal force acting on it will be mass multiplied with acceleration due to gravity.

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Work done = -15.68×0.75 = -11.76 J.

So the work is done by the object.

If the kinetic energy of the body at starting is 16 J, then the kinetic energy of the body at definitive position will be obtained as below.

Work done = change in kinetic energy

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Final Kinetic energy = - 11.76+16

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3 0
3 years ago
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