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tiny-mole [99]
3 years ago
8

according to Newton's third law what is the equal and opposite force to the downward force of gravity pulling on a man standing

in the woods
Physics
2 answers:
Fudgin [204]3 years ago
7 0

When you're talking about gravity, it's easy to identify the equal
opposite forces.

Gravity ALWAYS produces an equal pair of opposite forces. 
They both act between the centers of the two objects, one in
each direction.

Consider the equal pair of opposite gravitational forces between
you and the Earth.  One force acts on you, and draws you toward
the center of the Earth.  We call that force "your weight". 
The other one acts on the Earth, and draws it toward the center
of you.  Hardly anybody ever talks about that one, but the two
forces are equal ... your weight on Earth is equal to the Earth's
weight on you !

RideAnS [48]3 years ago
3 0

Answer: it is the pulling upward exerted by the man on the Earth.

Explanation:

Newton's third law states that the forces come in pair: the action force and the reaction force.

Whenever an object (call it object 1) exerts a force (action force) on a second object (object 2), an equal in magnitude and opposite in direction force (reaction force) is exerted by the second object on the object 1.

Consider the force of gravity, which is the downward pulling exerted by Earth on the man standing in the woods, the action force, then the reaction force, is the counteracting force exerted by the man on the Earth, and it is a pulling of the same magnitude of the gravity pulling but upward. The downward pulling is exerted on the man, but the upward pulling is exerted on the Earth.

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monitta

Answer:

Below

Explanation:

1) To find the average velocity of an object you can use this formula :

     v = ∆displacement / ∆time

     v = 200 m / 5 s

     v = 40 m/s

The average velocity of the turtle is 40 m/s

2) To find the distance an object can travel you can use this formula :

     d = (∆velocity)(∆time)

     d = (20m/s)(5s)

     d = 100 m

The cheetah can run 100 meters in 5 seconds

3) To find the amount of time it takes for an object to move :

     t = ∆displacement / ∆velocity

     t = 5mi / 20 mph

     t = 0.25 h

It would take this car 0.25 h to travel 5 miles at 20 mph

4) To find how far an object can go :

     d = (∆velocity)(∆time)

     d = (20mph)(3h)

     d = 60 mi

The car can drive 60 miles driving 20 mph for 3 hours

5) To find how far an object can go :

     d = (∆velocity)(∆time)

     d = (20mph)(30min)

     d = (20mph)(0.5h)

     d = 10 mi

The car can drive 10 miles driving 20mph for 30 minutes

6) To find how long it would take :

     t = ∆displacement / ∆velocity

     t = 10 m / 50 m/s

     t = 0.2 s

It would take the train 0.2 seconds for a train to travel 10 m at 50 m/s

7) To find how far :

     d = (∆velocity)(∆time)

     d = (670,000,000 mph)(1 yr)

     d = (670,000,000 mph)(8760 h)

     d = 5869200000000 mi

1 light year is 5869200000000 miles

Hope this helps! Best of luck <3

6 0
3 years ago
A ball is thrown at 25 m/s at an angle of 55 degrees.
yuradex [85]

Answer:65 seconds

Explanation:just had the quiz

4 0
3 years ago
When the course deviation indicator (CDI) needle is centered during an omnireceiver check using a VOR test signal (VOT), the omn
lilavasa [31]

Answer:

0° FROM or 180° TO

Explanation:

A course deviation indicator or the CDI may be defined as an avionics tool or instrument that is used in the aircraft navigation which is used to determine an aircraft's lateral position with relation to a course.

While using the VOT service, we should tune the VOT frequency of the VOR receiver. And with the CDI leveled centered, the omnibearing selector or the OBS should read as 0° with the TO/FROM indicator showing 'FROM'. Else the OBS should read as 180° with the TO/FROM indication showing 'TO.'

4 0
3 years ago
21/33
postnew [5]

Answer:

400N

Explanation:

5 0
3 years ago
A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis
Natali5045456 [20]

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

M_{before} = M_{after}

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

(m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

3 0
3 years ago
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