Answer:
4.47 m/s.
Explanation:
distance traveled, d = 10 miles
time, t = 1 hour
Speed of the runner, v = d / t
Speed of the runner = 10 miles / 1
Speed of the runner = 10 mph
1 mph ----------------------- 0.44704 m/s
10 mph -----------------------?
= 4.47 m/s
Thus, in 2 hours the distance traveled will change but the speed it still 10 mph or 4.47 m/s.
The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.
<h3>What is image distance?</h3>
This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.
To calculate the image distance, we use the formula below.
Formula:
- 1/f = 1/u+1/v........... Equation 1
Where:
- f = Focal length of the mirror
- v = Image distance
- u = object distance
From the question,
Given:
Substitute these values into equation 1 and solve for the image distance
- 1/0.45 = 1/0.25 + 1/v
- 2.22 = 4+1/v
- 1/v = 2.22-4
- 1/v = -1.78
- v = 1/(-1.78)
- v = -0.56 m
Hence, The image distance is -0.56 m.
Learn more about image distance here: brainly.com/question/17273444
Answer:
the sun is larger than the moon so it creates a shadow
<span>it would bond to the phosphate
</span>
Postitive ions have more protons than electrons, because protons are positively charged. Electrons have a negative charge, so if there were less protons than electrons the job would be negative. If there were the same amount of both, then the positive and negative charges balance each other out, making a neutral charge.
