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pogonyaev
3 years ago
5

Some runners have just started a race. They began at rest and are getting faster.What statement best describes the motion of the

runners at the beginning of the race (right after they start running)?
A. Acceleration and speed both remain constant.
B. Velocity and speed both remain constant.
C. Acceleration is positive and speed is increasing.
D. Velocity remains the same and speed is positive
Physics
1 answer:
olasank [31]3 years ago
8 0

Answer:

B

Explanation:

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What is the net force of a falling bowling ball that weighs 55 N and has 15 N of air resistance?
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3 years ago
The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivi
ahrayia [7]

To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

R = \rho \frac{L}{A}

Where,

R= Resistance of the conductor

\rho =Resistivity of the conductor material

L = Length

A = Cross-sectional area of conductor

With the previous values the area of the muscle (Real Muscle-82%)is,

A_m = (0.82)\pi r^2 = (0.82)\pi (12/2*10^{-2})^2

A_m = 9.274*10^{-3}m^2

Using the equation from Resistance we have that at the muscle the value is:

R_m = \rho \frac{L}{A}

R_m = \frac{13*(0.4)}{9.274*10^{-3}}

R_m = 560.70\Omega

At the same time we can make the same process to calculate the resistance of the fat, then

A_m = (0.18)\pi r^2 = (0.18)\pi (12/2*10^{-2})^2

A_m = 2.0357*10^{-3}m^2

The resistance of the fat would be,

R_f = \rho \frac{L}{A}

R_f = \frac{25*(0.4)}{2.0357*10^{-3}}

R_f = 4912.3\Omega

Then the total resistance in a set as the previously writen, i.e, in parallel is:

R=\frac{R_mR_f}{R_m+R_f}

R = \frac{(560.70)(4912.3)}{4912.3+560.70}

R = 502.62\Omega

We can here apply Ohm's law, then

I= \frac{V}{R}

I = \frac{1.5}{502.62}

I = 2.984*10^{-3}A

I = 2.984mA

3 0
4 years ago
Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, a
Blababa [14]

Answer: c a d b

Explanation:

4 0
3 years ago
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