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3 years ago

Background information about reflection and refraction of light

Physics

1 answer:

KIM [24]3 years ago

4 0

Answer:

reflection :

angle of reflection and angle of incidence is equal
Incident ray and reflect d ray plus normal lies on the same plan on a same point
light reflect uniformly if it is incident on a plan surface

refraction :

light will refrect if light goes from rare medium to a dense medium or vice versa
after the light is refracted, it retunes to its original direction
angle of incidence is not equal to the angle of refraction

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Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he p

Tomtit [17]

Answer:

B- He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.

Explanation: Dissolving Salt in water is a Chemical Change, Because the Salt arrangement is different in solid state than dissolved in water. As we can see in the image below, once the Salt is dissolved, it is separated into its ions, Na+ and Cl- Now, The evaporation process is a physical change, because the water doesn´t change its configuration H20 and it only changes its form, as we can see in the image below.

6 0

3 years ago

Read 2 more answers

A spaceship ferrying workers to moon Base i takes a straight-line pat from the earth to the moon, a distance of 384,000km, Suppo

GrogVix [38]

Answer:

95.78125%

18000 m/s

22233.33 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow v=0+20\times 15\times 60\\\Rightarrow v=18000\ m/s$

The velocity of the rocket at the end of the first 15 minutes is 18000 m/s which is the maximum speed of the rocket in the complete journey.

Distance traveled while speeding up

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 20\times 900^2\\\Rightarrow s=8100000\ m$

Distance traveled while slowing down

$s=18000\times 900+\dfrac{1}{2}\times -20\times 900^2\\\Rightarrow s=8100000\ m$

Distance traveled during constant speed

$384000000-(2\times 8100000)=367800000\ m$

Fraction

$\dfrac{367800000}{384000000}\times 100=95.78125\ \%$

Fraction of the total distance is traveled at constant speed is 95.78125%

Time taken at constant speed

$t=\dfrac{367800000}{18000}=20433.33\ s$

Total time taken is $900+20433.33+900=22233.33\ s$

6 0

3 years ago

What is the magnitude of the torque that the axle must apply to prevent the disk from rotating?

mihalych1998 [28]

The required torque at the axle, is given by the difference between the

moments of the applied forces.

The torque required is 19.62 N·m counterclockwise

Reasons:

The given parameters are;

Mass of the disk, m = 5.0 kg

Location of the axle = Half the radius of the disk

Diameter of the disk, D = 40 cm = 0.4 m

Applied mass, 0.1 m from the axle = 15 kg

Applied mass, 0.3 m from the axle = 10 kg

Required:

Magnitude of torque at the axle that prevent the disk from rotating

Solution:

Torque needed = Clockwise moment - Counterclockwise moment

Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m

Counterclockwise moment = 15 kg × 0.1 m × 9.81 m/s² = 14.715 N·m

τ + Counterclockwise moment = Clockwise moment

τ + 14.715 N·m = 34.335 N·m

Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m

Torque required, τ = 19.62 N·m counterclockwise

Learn more here:

brainly.com/question/19044661

brainly.com/question/19247046

The probable question drawing obtained from a similar question online is attached

7 0

3 years ago

Investigations allow for the control of variables.

Mila [183]

Dependent / Response Variable: factor or condition in a experiment that changes as a result of the independent variable; often called the responding variable. ... Constant: factors or conditions in an experiment that are kept the same in as trials of the experiment. Control: a set up without the variable being tested.

6 0

3 years ago

Write a question about how changing temperature affects the gas inside the sports ball

dmitriy555 [2]

Answer:

What happens to the pressure of the air inside a sport ball when it is heated?

Explanation:

We can answer this question by thinking at what happen at microscopic level.

In fact, when the gas inside the ball is heated, the molecules of the gas start moving faster. As a result, the rate of collision of the molecules against the internal surface of the ball increases: and therefore, the pressure of the gas inside the ball increases.

We can also see this by looking at the ideal gas law, which states that:

$pV=nRT$

where

p is the gas pressure

V is the gas volume

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

In this situation, the volume of the gas V is constant (since the ball has a constant volume), the number of moles n is also constant, as well as R. So we can rewrite this as

$p \propto T$

so we see that the pressure is directly proportional to the temperature: therefore, when the ball is heated, the pressure inside the ball increases.

6 0

3 years ago