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Sedaia [141]
2 years ago
12

The SI base units have the dimensions of: Group of answer choices mass, weight, time length, density, time mass, length, time we

ight, length, time mass, length, speed
Physics
1 answer:
Nutka1998 [239]2 years ago
8 0

The SI base units have the dimensions of: length, mass and time.

<h3>What are SI base units?</h3>

The SI base units are the internationally accepted system of units of fundamental quantities.

These SI base units consist of system of units of measurement starting with seven base units, which are as follows:

  • second (s): the unit of time
  • metre (m): The unit of length kilogram (kg): the unit of mass
  • ampere (A): the unit of electric current
  • kelvin (K): the unit oftemperature
  • mole (mol.): the unit of amount of substance
  • candela (cd):the unit of luminous intensity

Learn more about SI base units

brainly.com/question/4950932

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Mr Ndlovu works in centurion and works at Rosebank.It takes him 13minutes to get to work and he needs to be there at 08h15
VARVARA [1.3K]

Answer:

8:02 no less

Explanation:

8:15 - 13mins = 8:02

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What sort of fitness component would dance be<br> categorized under
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Answer:

aerobic fitness

Explanation:

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3 years ago
You walk six blocks east along 12th Street, then three blocks west, then one block east, then six blocks east, then seven blocks
Oksana_A [137]
Displacement depends upon the path taken as it is a vector.

From your problem above we would have a total displacement of;
Defining +x direction as east and -x direction as west

6east-3west+1east+6east-7west

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5 0
3 years ago
Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

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