Question

Dez pours water (n 1.333) into a container made of crown glass (n 1.52). The light ray in ner made of crown glass (n = 1.52). The light ray in glass incident on the glass-to-liquid boundary makes an angle of 30.0 with the normal. Find the angle of the corresponding refracted ray

Answer 1

Answer:

The angle of the corresponding refracted ray is 34.84°

Explanation:

Given that,

Refractive index of water n= 1.33

Refractive index of glass n= 1.52

Incident angle = 30.0°

We need to calculate the refracted angle

Using formula of Snell's law

$n_{i}\sin i=n_{r}\sin r$

Put the value into the formula

$\sin r=\dfrac{n_{i}\sin i}{n_{r}}$

$\sin r=\dfrac{1.52\times\sin30}{1.33}$

$\sin r=0.5714$

$r=sin^{-1}0.5714$

$r = 34.84^{\circ}$

Hence, The angle of the corresponding refracted ray is 34.84°