Yes. This equation given:
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" y = (½)x + 4 " ; in point-slope form; also known as: "slope-intercept form" ; is:
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" y = (½)x + 4 " .
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In other words, the equation given is ALREADY written in "point-slope form" ; or, "slope-intercept form".
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Note: An equation that is written in "point-slope form"
(or, "slope-intercept form"), is written in the format of:
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" y = mx + b " ;_________________
in which:_________________
"y" is a single, "stand-alone" variable on the "left-hand side of the equation"; "m" is the coefficient of "x"; also:
"m" is the slope of the line; which is what we want to solve for;
"b" is the "y-intercept"; or more precisely, the value of "x"
(that is; the "x-coordinate") of the point at which "y = 0";
that is, the value of "x" ; or the "x-coordinate" of the point at which
the graph of the equation crosses the "x-axis".
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Note that in our given equation, which is written in "point-slope form" (or, "slope-intercept form" — that is: " y = mx + b " ;
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which is: " y = (½)x + 4 " ;
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we have:
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"y" isolated as "stand-alone" variable on the "left-hand side" of the equation;
m = ½ ;
b = 4 .
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I dunno actually D: I think it's 1.6 sorry I really don't know leave a 1 star if you have to!
Answer:
θ = π + periods of 2π
Sin (π + 2π) = 0
Cos (π + 2π) = -1
Tan (π + 2π) = 0
Step-by-step explanation:
Sin (θ)=0 implies that θ only can be 0 or π plus periods of 2π:
θ = 0+2π
θ = π+2π
For Cos(θ) the values only can be:
Cos (0+2π) = 1 and
Cos (π+2π) = -1
from this, only Cos (π+2π) < 0
So θ only can be θ=π+2π
The area of your circle is about 530.93 m
The diameter of your circle is 26 m, just multiply your radius by 2
The circumference of the circle is about 81.68
The equation to finding the area is
pi x r x 2
3.14 times 13 times 2
The equation to finding the diameter
r x 2
radius times 2
The equation for finding circumference
pi x d
3.14 times 26
Let me know if im wrong, otherwise I want brainliest, PLEASE!!
