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tankabanditka [31]
3 years ago
14

Maurice is making snacks for his friends by putting equal amounts of trail mix in each bag. He started with 4 4/5 cups, but his

got hungry and ate 15cup of the mix himself. He then portioned 3/5 cup of mix evenly into each bag for the friends. How many complete bags was Maurice able to make.
PLZ HELPPP MEEE I NEED IT NOW I WILL GIVE BRAINLEIST AND SHOUT U OUT PLZZZZZ I NEED HELP PLZ HELP ME
Mathematics
1 answer:
sashaice [31]3 years ago
6 0

Answer:

\boxed{7}

Step-by-step explanation:

1. Subtract what Maurice ate

4⅘ c

<u>- ⅕ c </u>

4⅗ c

2. Calculate the number of bags

\text{Number of bags }= \dfrac{\text{Total volume}}{\text{Volume of each bag}} = 4\frac{3}{5} \div \frac{3}{5}

(a) Convert the mixed number to an improper fraction

4\frac{3}{5} \div \frac{3}{5} = \frac{23}{5}\div\frac{3}{5}

(b) Invert the denominator and change division to multiplication

\frac{23}{5}\div\frac{3}{5} = \frac{23}{5}\times \frac{5}{3}

(c) Cancel the 5s

\frac{23}{5}\times \frac{5}{3} = \frac{23}{3}

(d) Convert the improper fraction to a mixed number.

\frac{23}{3} = \mathbf{7\frac{2}{3}}\\\text{Maurice can make $\boxed{\mathbf{7}}$ complete bags of trail mix.}

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bagirrra123 [75]

(d):  y = mx+n

m = -2/3 ⇒ y = (-2/3)x +n

A(-4,  6) ∈ d  ⇒ 6 = (-2/3)·(-4) +n ⇒ 6 = 8/3 +n ⇒

⇒ n = 6 - 8/3 ⇒ n = 10/3

Now, we have:

y = (-2/3)x +10/3


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