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kenny6666 [7]
3 years ago
9

Ethane, a minority component of natural gas, burns to form carbon dioxide and water according to this reaction: 2H3C−CH3(g)+7O2(

g)→4CO2(g)+6H2O(g) Note that the average bond energy for the breaking of a bond in CO2 is 799 kJ/mol. Use average bond energies to calculate ΔHrxn for this reaction.
Chemistry
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:

The answer is -2812 kJ.

Explanation:

I got this answer from another person:

The following values will vary depending on the source;

C-C  347 kJ/mole;  C-H 414 kJ/mole;  O-H 464 kJ/mole ;  O=O  498 kJ/mole

It takes energy to break bonds and energy is released when bonds are formed.

Ethane has 1 C-C bond  ;  1(347 )  347 kJ/mole

Ethane has 6-C-H bonds;  6(414) = 2484 kJ/mole

Break the bonds of 1 mole of C2H6  =  2831 kJ

2 moles of ethane in balanced equation:  2(2831 kJ) =  5662 kJ

Break 7 O=O bonds  =  7(498 ) = 3486

Total energy to break all bonds: 5662 +   2486 = +9148 kJ

2C=O bond formed in CO2  = 2(799) =  1598 kJ/mole

4 moles of CO2 = 4(1598) =  6392

2(O-H) bonds in H2O =  2(464)  =  928 kJ/mole

6 moles of H2O  =  6(928 kJ) = 5568

Total energy released =  6392 + 5568 = 11,960 kJ  

The sign of this energy is -11,960 since it is exothermic.

Energy change for 2 moles of ethane = -11,960 + 9148 = -2812 kJ

ΔHrxn = -2812 kJ

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4 years ago
The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If t
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Answer:

The catalyzed reaction will take time of 5.11\times 10^{-8} years.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate of reaction with catalyst

K_1 = rate of reaction without catalyst

Ea_2 = activation energy with catalyst  = 59.0 kJ/mol = 59000 J/mol

Ea_1 = activation energy without catalyst  = 184 kJ/mol = 184000 J/mol

R = gas constant

T = temperature = 600K

Now put all the given values in this formula, we get:

\frac{K_2}{K_1}=e^{\frac{184,000 kJ-59000 kJ}{R\times 300}}=7.632\times 10^{10}

The reaction enhances by 7.632\times 10^{10}  when catalyst is present.

Time taken by reaction without catalyzed = 3900 years

Time taken by reaction with catalyzed = x

x=\frac{3900 year}{7.632\times 10^{10}}=5.11\times 10^{-8} years

The catalyzed reaction will take time of 5.11\times 10^{-8} years.

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3 years ago
Calculate the volume of liquid in the tank sketched below. Give your answer in liters, and round to the nearest 0.1 L.
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Answer:

The answer is 18.9

Explanation:

3 0
3 years ago
14. An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km
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Answer:

27 min

Explanation:

The kinetics of an enzyme-catalyzed reaction can be determined by the equation of Michaelis-Menten:

v = \frac{vmax[S]}{Km + [S]}

Where v is the velocity in the equilibrium, vmax is the maximum velocity of the reaction (which is directed proportionally of the amount of the enzyme), Km is the equilibrium constant and [S] is the concentration of the substrate.

So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min

If Km is a thousand times smaller then [S], then

v = vmax[S]/[S]

v = vmax

vmax = 1.33 μmol/min

For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:

vmax = 1.33/3 = 0.443 μmol/min

Km will still be much smaller then [S], so

v = vmax

v = 0.443 μmol/min

For 12 μmol formed:

0.443 = 12/t

t = 12/0.443

t = 27 min

7 0
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What differs from between a radioactive isotope and a stable isotope
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A stable isotope has just<em> the right number of neutrons for the number of protons </em>(the <em>n:p ratio</em>) to hold the nucleus together against the repulsions of the protons.

A radioactive isotope has either too few or too many neutrons for the nucleus to be stable,

The nucleus will then emit <em>alpha, beta, or gamma radiation</em> in an attempt to become more stable.  

7 0
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