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EastWind [94]
3 years ago
5

Jvhftfcticgvigybvhbjnjndjanvjisn

Physics
2 answers:
nirvana33 [79]3 years ago
4 0

Answer:

dnndmssnxnxdnskkaamzmzma nzz.

fenix001 [56]3 years ago
4 0
SJJSKESKIWKALWLSOWOWOWKSKWWKW
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Define valence electrons
lisabon 2012 [21]

Answer:

In chemistry and physics, a valence electron is an outer shell electron with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.

Explanation:

3 0
4 years ago
Read 2 more answers
What is the relationship between wavelength of light and the quantity of energy per photon?
slamgirl [31]

Answer:

The quantity of energy per photon is inversely proportional to the wavelength of the light.

Explanation:

Energy of light is given as

E = hf

where E = energy of the photons,

f = frequency of the light

If the number of photons = n

(E/n) = (h/n) f

Let (E/n) = E'

(h/n) = h'

But the frequency of light is related to wavelength through the relation

v = fλ

where v = speed of light = c

λ = wavelength of light

f = (c/λ)

E' = h' f

Substituting for f

E' = h' (c/λ)

h' and c are both constants, h'×c = K

E' = (K/λ)

So, the quantity of energy per photon is inversely proportional to the wavelength of the light.

Hope this Helps!!!

3 0
4 years ago
Read 2 more answers
Lol somebody tell me the answer ill also give 5 stars
AnnyKZ [126]

Answer:

i believe it's carbon. i may be wrong. but i haven't done atoms in almost 2 years. sorry if it's wrong. :)) hava good day

Explanation:

4 0
3 years ago
Read 2 more answers
A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an ampl
Sati [7]

Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s  d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.

4 0
3 years ago
What is the potential energy of a 2kg object placed 6m above<br> the surface of the Earth?
zalisa [80]

Answer:117.6joules

Explanation:

Mass(m)=2kg

Height(h)=6m

Acceleration due to gravity(g)=9.8m/s^2

Potential energy(PE)=?

PE=m x g x h

PE=2 x 9.8 x 6

PE=117.6joules

8 0
3 years ago
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