Answer:
D) force,cause, displacement
Answer:
The new concentration is 0.125 M.
Explanation:
Given data:
Initial volume V₁ = 125.0 mL
Initial molarity M₁ = 0.150 M
New volume V₂ = 25 mL +125 mL = 150 mL
New concentration M₂ = ?
Solution:
M₁V₁ = M₂V₂
0.150 M × 125 mL = M₂ × 150 mL
M₂ = 0.150 M × 125 mL / 150mL
M₂ = 18.75 M.mL/150 mL
M₂ = 0.125 M
The new concentration is 0.125 M.
<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm
<u>Explanation:</u>
For the given chemical equation:
![PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)](https://tex.z-dn.net/?f=PCl_5%28g%29%5Crightleftharpoons%20PCl_3%28g%29%2BCl2%28g%29)
The expression of
for above reaction follows:
![K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7Bp_%7BCl_2%7D%5Ctimes%20p_%7BPCl_3%7D%7D%7Bp_%7BPCl_5%7D%7D)
We are given:
![K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm](https://tex.z-dn.net/?f=K_p%3D0.497%5C%5Cp_%7BPCl_3%7D%3D0.651atm%5C%5Cp_%7BPCl_5%7D%3D0.471atm)
Putting values in above equation, we get:
![0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm](https://tex.z-dn.net/?f=0.497%3D%5Cfrac%7Bp_%7BCl_2%7D%5Ctimes%200.651%7D%7B0.471%7D%5C%5C%5C%5Cp_%7BCl_2%7D%3D0.360atm)
Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm
Well I wouldn't quite call it a third eye but yes we have the ability to see things if we connect to our inner selves