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2 years ago

How many inner shell electrons does beryllium have?

Chemistry

2 answers:

stepladder [879]2 years ago

8 0

Beryllium has two inner shell electrons

olchik [2.2K]2 years ago

5 0

And two 2s electrons in the Be atom. Its electron configuration is thus 1s22s2or[He]2s2 The symbol [He] denotes the inner shell of two 1s electrons which have the same configuration as the noble gas He. The beryllium atom is noticeably smaller than the lithium atom

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What’s the difference between sucrose, fructose and glucose?

Sergeeva-Olga [200]

Answer:

Explanation:

Sucrose Is Made up of Glucose and Fructose

Glucose is a simple sugar or monosaccharide.

Fructose, or “fruit sugar,” is a monosaccharide like glucose

5 0

3 years ago

What can be absorbed or produced as the result of a chemical reaction???

tia_tia [17]

Heat can be absorbed or produced

6 0

3 years ago

A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of

inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 $\frac{g}{c m^{3}}$

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

$\rho=\frac{m}{v}$ and from this

$m=\rho \times v$

Where, m=mass of the cylinder

$\rho$ =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

$v=\pi r^{2} h$

Where $\pi$ =3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, $v=3.14 \times 12^{2} \times 44$

v=3.14 \times 144 \times 44

$v=19895.04 \mathrm{cm}^{3}$

And we know that, $m=\rho \times v$

Substitute the known values in the above equation we get

$m=8.90 \times 19895.04$

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

4 0

3 years ago

Consider the following reaction: 2CH3OH ---> 2CH4+O2 delta H= +252.8kJ. Calculate the amount of heat transferred when 22.0g o

nydimaria [60]

To calculate the amount of heat transferred when an amount of reactant is decomposed, we must look at the balanced reaction and its corresponding heat of reaction. In this case, we can see that 252.8 kJ of heat is transferred per 2 moles of CH3OH used. When 22 g of CH3OH is used, 86.9 kJ is absorbed.

4 0

2 years ago

Help in chem please!!!!!!

IgorLugansk [536]

This is a one-step unit analysis problem. Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

$1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}$

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0

3 years ago