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poizon [28]
2 years ago
9

What two processes below are MOST SIMILAR?

Chemistry
2 answers:
mars1129 [50]2 years ago
8 0
The first one in my opinion
SpyIntel [72]2 years ago
4 0
The last one is the most similar in my opinion
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2C8H18 (1) + 2502 (g) --> 16CO2 (g) + 18H2O (g)
Makovka662 [10]

Answer:

One gallon of octane produces approximately 7000 L of carbon dioxide.

Note:

I believe that the mass of octane should have been given as 2661 g. However, I understand that your instructor probably gave you this problem, so I will use 4000 g for the approximate mass of one gallon of octane. You can rework the problem on your own, substituting the correct masses of octane if you wish.

Step1. You must first determine the number of moles that are in 4000 g of octane, using the molar mass of octane. Step 2. Then you must determine the number of moles of carbon dioxide that can be produced by that number of moles of octane, based on the mole ratio between octane and carbon dioxide in the balanced equation. Step 3. Then use the ideal gas law to determine the volume in liters of carbon dioxide that can be formed.

5 0
2 years ago
How many atoms are in 5.2 moles of Na ?
Nastasia [14]

One mole of a substance is defined by Avogadro as consisting of 6.022 x 1023 atoms. This is Avogadro's number. To calculate the number of atoms in two moles of sodium, use dimensional analysis. 2.0 moles Na x 6.022⋅1023g1mol=1.20⋅1024 atoms of Na

8 0
2 years ago
Calculate the density (in g/mL) of a liquid that has a mass of 0.115g and a volume of 0.000265 L
notsponge [240]

density is mass/volume so we do

.115/.000265

433.962 g/mL


5 0
2 years ago
`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
PLEASE ANSWER THIS FAST
Fofino [41]

Answer:

A and c MgSO4 and HNO3

8 0
3 years ago
Read 2 more answers
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