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1 year ago

You have dissolved 10 g sodium oxide in 200 ml water.calculate concentration of the solution

Chemistry

1 answer:

e-lub [12.9K]1 year ago

8 0

Answer:

0.85 Molar Na2O

Explanation:

Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).

(10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.

Molar is a measure of concentration. It is defined as moles/liter. A 1 M solution contains 1 mole of solute per liter of solvent. [200 ml water = 0.2 Liters water.]

In this case, we have 0.161 moles Na2O in 0.200 L of solvent.

(0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O

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In a chemical equation what name does the left side have

Pachacha [2.7K]

A chemical equation is a short hand expression of a chemical reaction. There aretwo<span> parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products.</span>

4 0

3 years ago

Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th

serg [7]

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of $O_2$

So, 155. mmole of HCl react with $\frac{155.}{4}\times 1=38.75$ mmoles of $O_2$

That means, $O_2$ is excess reagent and $HCl$ is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

7 0

3 years ago

Calculate the number of Li atoms in 7.8 mol of Li.

Gwar [14]

<h3>Answer:</h3>

4.7 × 10²⁴ atoms Li

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.8 mol Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 7.8 \ mol \ Li(\frac{6.022 \cdot 10^{23} \ atoms \ Li}{1 \ mol \ Li})$
Multiply/Divide: $\displaystyle 4.69716 \cdot 10^{24} \ atoms \ Li$