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liubo4ka [24]
3 years ago
8

Ergosterol, a precursor of vitamin D, has δmax = 282 nm and molar absorptivity ε = 11,900 M-1cm-1. What is the concentration of

ergosterol in a solution whose absorbance A = 0.43 with a sample pathlength l = 1.00 cm.?
Chemistry
1 answer:
meriva3 years ago
3 0

Answer:

3.6 × 10⁻⁵ M

Explanation:

Ergosterol has a maximum absorbance at λ = 282 nm. The absorbance of an analyte is related to its concentration through the Beer-Lambert's law.

A = ε × <em>l</em> × c

where,

A: absorbance

ε: molar absorptivity

<em>l</em>: optical path length

c; molar concentration

c = A / ε × <em>l </em>= 0.43 / (11,900 M⁻¹cm⁻¹) × 1.00 cm = 3.6 × 10⁻⁵ M

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1-The chemical potential energy of bond A is greater than the chemical potential energy of bond B. Which statement best explains
Tju [1.3M]

It should be noted that bond A has greater energy because C. The atoms in bond A are held more tightly together than the atoms in bond B.

<h3>Bond</h3>

The relationship between the bond energies of nitrogen, iodine, and fluorine gases is that the bond in nitrogen gas is the most difficult to break.

From the information given, the molecule with the greatest bid energy is CH4. The bind energy measures the bond strength that the chemical bond has.

Also, the bond energy of the reactants in reaction 1 is greater than the bond energy of the reactants in reaction 2. Due to this, reaction 1 requires a greater input of energy than reaction 2.

Lastly, the difference in the bond energy of Chlorine and Bromine is that Bromine has more electron levels than chlorine.

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3 years ago
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Transport of aspirin is expected to be faster in the ____. The speed of nonmediated absorption depends strongly on the polarity
slega [8]

Answer:

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Explanation:

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7 0
3 years ago
Flourine is more reactive than chlorine​
IRISSAK [1]
Justification for your answer

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Chlorine is less reactive than fluorine because the outer electrons in a chlorine atom are further from the nucleus than the outer electrons in a fluorine atom. It is harder for a chlorine atom to gain an electron than it is for a fluorine atom.

There are three things to consider every single time relative reactivity is unknown; atomic radius, shielding, and number of electrons. The reactivity is the halogens ability to gain an electron, so number of electrons already in the atom plays a vital role. Chlorine has more electrons so repels a reacting electron with greater force than fluorine, making it less likely to react.

Fluorine also has fewer electron shells than chlorine, so there are fewer electrons between the positive nucleus and the reacting electron to essentiallly block, or weaken, the electromagnetic attraction. This is shielding. Lastly, fluorine is much smaller molecule than chlorine, and the shorter distance, or radius, between the nucleus and the electron again makes it more likely to attract the electron and react to gain a noble gas configuration.

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7 0
3 years ago
Read 2 more answers
Part A
inysia [295]

Pressure of the gas inside the container is 662.59 torr.

<h3>What is ideal gas law?</h3>

The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).

The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.

V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.

If P and T are different values and n and V are constants, then

(P₁T₂) = (P₂T₁).

P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,

P₂ = ??? torr, ​T₂ = 62°C + 273 = 335 K.

∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.

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5 0
1 year ago
Given the partial equation: NO3− Pb2 → NO2 Pb4 , balance the reaction in acidic solution using the half-reaction method and fill
Fed [463]

Answer : The balanced reaction in acidic solution is,

2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O

Explanation :

The given partial equation is,

NO_3^-+Pb^{2+}\rightarrow NO_2+Pb^{4+}

First we have to separate into half reaction. The two half reactions are:

NO_3^-\rightarrow NO_2

Pb^{2+}\rightarrow Pb^{4+}

Now we have to balance the half reactions in acidic medium, we get:

NO_3^-+2H^++1e^-\rightarrow NO_2+H_2O       ............(1)

Pb^{2+}\rightarrow Pb^{4+}+2e^-     ............(2)

Now we have to balance the electrons of the half reactions. When we are multiplying the equation (1) by 2, we get

2NO_3^-+4H^++2e^-\rightarrow 2NO_2+2H_2O  ...........(3)

Now we have to add both the half reactions (2) and (3), we get the final balanced chemical reaction.

2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O

3 0
3 years ago
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