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ANTONII [103]
3 years ago
12

Lenz’s law states that an induced magnetic field in a conductorA. Opposes the change in flux through the conductor.B. Opposes th

e applied magnetic field.C. Induces a matching electric field that causes a current.D. Opposes the applied flux through the conductor.
Physics
2 answers:
Paha777 [63]3 years ago
7 0

Answer:

D. Opposes the applied flux through the conductor.

Explanation:

  • <em><u>According to the Lenz's law, the direction of induced e.m.f is such that it generates a current which in turn produces a magnetic field that would oppose the change causing it.</u></em>
  • In other words, the direction of any magnetic induction effect is such that it opposes the cause of the effect.
  • Therefore; an induced magnetic field in a conductor, opposes the applied flux through the conductor.
Marina86 [1]3 years ago
3 0

Answer:

A. Opposes the change in flux through the conductor.

Explanation:

Here we can say that as per Lenz law the induced EMF direction is always opposite in the direction of the rate of change in flux in the coil.

If the flux is increasing in the closed loop due to some external source of EMF then in that case the induced EMF will will always induced a current that will oppose the external change increasing flux

And same if applicable is the external flux is decreasing so in that case the induced current in loop will always in such a direction that will increase the flux.

So we can say that induced EMF is given by Faraday's law but the direction of induced current is only by the help of Lenz law

EMF = - \frac{d\phi}{dt}

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A particle moves along the x-axis according to x(t)=10t−2t²m. (a) What is the instantaneous velocity at t = 2 s and t = 3 s? (b)
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Answer:

a) v(2) = 2m/s, v(3) = -2m/s

b) speed at t = 2s is 2m/s

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Explanation:

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(b) The speed would be the same as velocity without the direction

speed at t = 2s is 2m/s

speed at t = 3s is 2m/s

(c) The average velocity between t = 2s and t = 3s is distance it travels over period of time

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3 years ago
Your electric drill rotates initially at 5.35 rad/s. You slide the speed control and cause the drill to undergo constant angular
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Answer:

The  angular displacement  is  \theta  =  29.6 \ rad

Explanation:

From the question we are told that

     The initial angular speed is  w =  5.35 \ rad/s

      The angular acceleration is  \alpha  =  0.331 rad /s^2

      The time take is  t =  4.81 \ s

     

Generally the angular displacement is mathematically represented as

          \theta  =  w * t  + \frac{1}{2} \alpha  * t^2

substituting values

         \theta  =  5.35 * 4.81  + \frac{1}{2}  *  0.331  * (4.81)^2

         \theta  =  29.6 \ rad

3 0
3 years ago
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