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3 years ago

6

Imagine that it is summer solstice in the Northern Hemisphere. What is the date, and where is the Sun? What is happening in the

Southern Hemisphere? Please help

1 answer:

Alexandra [31]3 years ago

4 0

21 june is the date......hopi it will help

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A positive statement is:________. a. reflects oneâs opinions. b. can be shown to be correct or incorrect. c. a value judgment. d

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Answer:

b

Explanation:

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3 years ago

A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward

Ksenya-84 [330]

I think th<span>e upward acceleration of the rocket during the burn phase is 7.</span>8 m/s2

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4 years ago

An emergency first aid kit should include

AlekseyPX

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4 years ago

A transverse wave has a frequency of 200 Hz with a wavelength of 1.0 m. Determine the speed

Lana71 [14]

Answer:

200 m\ s Ans .....

Explanation:

Data:

f = 200 Hz

w = 1.0 m

v = ?

Formula:

v = f w

Solution:

v = ( 200)(1.0)

v = 200 m\s <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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3 years ago

A wheel of diameter 78 cm has an axle of diameter 14.8 cm. A force 150 N is exerted along the rim of the wheel.What force should

bezimeni [28]

Answer:

F = 263.51 N

Explanation:

given,

diameter of wheel = 78 cm

diameter of axle = 14.8 cm

Force exerted on the rim of wheel = 150 N

Force applied outside the axle = ?

To prevent rotation wheel from rotating the Force 'F' should be applied outside of the axle.

Net momentum about the center of mass should be zero

now,

Moment of about center due to 150 N = moment about center due to F on axle

$50\times \dfrac{78}{2}=F\times \dfrac{14.8}{2}$

7.4 F = 1950

F = 263.51 N

Hence, Force exerted outside of the axle in order to prevent the wheel from rotating is equal to 263.51 N.

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4 years ago