Answer:Habituation is a simple learned behavior in which an animal gradually stops responding to a repeated stimulus.
Imprinting is a specialized form of learning that occurs during a brief period in young animals—e.g., ducks imprinting on their mother.
In classical conditioning, a new stimulus is associated with a pre-existing response through repeated pairing of new and previously known stimuli.
In operant conditioning, an animal learns to perform a behavior more or less frequently through a reward or punishment that follows the behavior.
Some animals, especially primates, are capable of more complex forms of learning, such as problem-solving and the construction of mental maps.
Introduction
If you own a dog—or have a friend who owns a dog—you probably know that dogs can be trained to do things like sit, beg, roll over, and play dead. These are examples of learned behaviors, and dogs can be capable of significant learning. By some estimates, a very clever dog has cognitive abilities on par with a two-and-a-half-year-old human!
Explanation:
Answer:
zirconium
Explanation:
Given, Mass of AgBr(s) = 23.0052 g
Molar mass of AgBr(s) = 187.77 g/mol
The formula for the calculation of moles is shown below:
Thus,
The reaction taking place is:
From the reaction,
4 moles of AgBr is produced when 1 mole of 
undergoes reaction
1 mole of AgBr is produced when 1 / 4 mole of undergoes reaction
0.1225 mole of AgBr is produced when 
mole of undergoes reaction
Moles of got reacted = 0.030625 moles
Mass of the sample taken = 12.5843 g
Let the molar mass of the metal = x g/mol
So, Molar mass of = x + 4 × 79.904 g/mol = 319.616 + x g/mol
Thus,
Solve for x,
we get, x = 91.2999 g/mol
<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>
The wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
Answer:
Explanation:
Since, wavelength, frequency and speed of sound waves are related to each other, we can determine a single parameter with the help of other two parameters. So in this case, the frequency of different notes are given along with their common speed. So as the frequency is inversely proportional to the wavelength then in this case, the wavelength of the notes will be maximum for C1 and minimum for 3951.1 Hz.
Wavelength = Speed / Frequency
Wavelength for C1 note = 340 / 32.7 =10.40 m
Similarly, the wavelength for A6 note = 340/1760=0.193 m
And, the wavelength for B7 note = 340/3951.1 = 0.086 m
So, the wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
