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g100num [7]
2 years ago
11

How is nuclear fusion different from an explosion from chemical reactions

Physics
1 answer:
ELEN [110]2 years ago
8 0

Answer:The main difference between these two processes is that fission is the splitting of an atom into two or more smaller ones while fusion is the fusing of two or more smaller atoms into a larger one.

Explanation:Protons and neutrons make up a nucleus, which is the foundation of nuclear science.

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Do you like genetic engineering explain even if there is no answer box still answer in the commets
liubo4ka [24]

Answer:

yes it is so awesome

Explanation:

4 0
3 years ago
You can tell from reading this passage that -
Romashka-Z-Leto [24]

Answer: B or "diamonds are rare,valuable gems".

Explanation:

since the link does not show very much, I don't know if A is correct or not. D is incorrect because that  is an opinion. C is incorrect.

4 0
3 years ago
6. An object moves along the x-axis. The graph shows its position x as a function of time t. Find
raketka [301]

Answer: 1.5 m/s

Explanation:

9-3/5-1= 6/4= 3/2= 1.5

Used x2-x1/t2-t1 to get average velocity from point b to c

7 0
3 years ago
To test the performance of its tires, a car travels along a perfectly flat (no banking) circular track of radius 130 m. The car
marysya [2.9K]

Answer:

0.739

Explanation:

If we treat the four tire as single body then

W ( weight of the tyre ) =  mass × acceleration due to gravity (g)

the body has a tangential acceleration = dv/dt = 5.22 m/s², also the body has centripetal acceleration to the center = v² / r

where v is speed 25.6 m/s and r is the radius of the circle

centripetal acceleration = (25.6 m/s)² / 130 = 5.041 m/s²

net acceleration of the body = √ (tangential acceleration² + centripetal acceleration²) = √ (5.22² + 5.041²) = 7.2567 m/s²

coefficient of static friction between the tires and the road = frictional force / force of normal

frictional force = m × net acceleration / m×g

where force of normal = weight of the body in opposite direction

coefficient of static friction = (7.2567 × m) / (9.81 × m)

coefficient of static friction = 0.739

4 0
3 years ago
Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed o
Mrac [35]

Answer:

The distance between the two slits is 1.2mm.    

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.  

Therefore, d can be isolated from equation 1.

d = L\frac{\lambda}{\Lambda x}  (2)

Notice that it is necessary to express L and \lambda in units of millimeters.

L = 4m \cdot \frac{1000mm}{1m} ⇒ 4000mm

\lambda = 600nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 0.0006mm

d = (4000mm)\frac{0.0006mm}{2mm}

d = 1.2mm

Hence, the distance between the two slits is 1.2mm.

6 0
3 years ago
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