The magnitude of normal force that floor exerts on chair is 100.83N
<u>Explanation:</u>
Given:
Weight of chair, W = 75N
Applied force, F = 42N
Angle, θ = 38°
Normal force, n = ?
We know,
Vertical component of the force = F sinθ
= 42 X sin38°
= 42 X 0.615
= 25.83N
Total normal force acting on the chair = 75N + 25.83N
= 100.83N
Therefore, the magnitude of normal force that floor exerts on chair is 100.83N
The electrons in an atom can only occupy certain allowed energy levels. ... Only certain energy levels are allowed, so only certain transitions are possible and hence specific wavelengths are emitted when an electron drops to a lower energy level
Explanation:
C or b because they both have the same product
Answer:
4 A
Explanation:
Firstly we need to calculate the equivalent resistance. Since, two resistors of 6 connected in parallel, so equivalent resistance will be given by,
1/R = 1/R1 + 1/R2
1/R = (1/6 + 1/6) Ω
1/R = (1 + 1)/6 Ω
1/R = 2/6 Ω
R = 6/2 Ω
<u>R = 3 Ω</u>
We know that,
V = IR
- <em>V</em> denotes p.d (12V)
- <em>I</em> denotes current
- <em>R</em> denotes resistance (3 Ω)
12 = I × 3
12 ÷ 3 = I
<u>4 Ampere = I</u>