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Veseljchak [2.6K]
3 years ago
10

Which of the following is true about the easy walk harness

Physics
2 answers:
Svetllana [295]3 years ago
6 0
<span>the easy walk harness should be looser on the dog than other harnesses</span>
tiny-mole [99]3 years ago
3 0

Answer:

The answer is option A

the leash always attaches to the easy walk harness in the front.

Explanation:

Attaching the leash to both the chest ring of the harness AND the leash ring of a regular collar helps to keep the harness in place and also prevents escape. See the diagram below


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What feature best distinguishes one form of electromagnetic energy from another?
anastassius [24]

The family of electromagnetic waves ranges from the Long Radio waves to the gama rays.

All of that contain electromagnetic energy and move at the speed of light.

But what distinguish one from another is their wavelengh.

Or, if you like, its counterpart: their frequency. (as can be seen in the equation c = λ . f   where c is the speed of light, λ is the wavelengh and f is the frequency).

The shorter the wavelengh (the greater the frequency) more powerful (more energy it contains) is the electromagnetic wave.

From all the different kinds of electromagnetic waves of the spectrum, the less powerful (less energetic) are the Long Radio waves (λ in metres) and the more powerful ones are the gama rays (λ in 10^{-12} m).

:-)

3 0
3 years ago
We use electrical devices leopard deuce motion, light, and sound. Which aspect of energy explains why these devices are possible
poizon [28]

Answer:

B) Energy can change from one form to another

Explanation:

It goes from electrical energy from the mains into motion, light and sound

3 0
3 years ago
Which type of energy is the original source for the energy that food molecules can provide?
Svet_ta [14]

Answer:

Chemical potential energy

Explanation:

which is used to for any form of energy.

4 0
3 years ago
Nuclear fusion has not yet been harnessed as an energy source because
maksim [4K]

Before getting an answer for it first we have to understand nuclear fusion.

Nuclear fusion is a thermo-nuclear reaction in which two  light unstable nuclei will form a heavy stable nuclei. In this process there will be some mass defect which will be converted into energy as per Einstein's mass energy equivalence theorem.

The theorem is stated as E = mc^{2} where c is the velocity of light and m is the mass converted into energy.

One take an example of fusion in sun where 4 hydrogen atoms combine to form a helium nucleus which are explained below-

                                                      H_{1}^{1}+H_{1} ^{1} =H_{1} ^{2} +e_{+1} ^{0} +energy

                                                      H_{1} ^{2} +H_{1} ^{1} =He_{2} ^{3} +energy

                                                      He_{2} ^{3}+H_{1} ^{1} =He_{2} ^{4} +e_{+1} ^{0} +energy

                                                       -----------------------------------------------------------------------

                                                        4H_{1} ^{1} = He_{2} ^{4} +2e_{+1} ^{0} +energy

Here e_{+1} ^{0} is the positron.

In this process very high temperature is needed which is approximately equal to the temperature of the sun i.e 10^{6} K

Such temperature is very difficult to initiate the reaction on the earth surface. It should be carried out in an sustainable way also .Otherwise It will cause nuclear hazards.

6 0
3 years ago
Read 2 more answers
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
2 years ago
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