Can somebody help please?
1 answer:
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Answer:
(a) Compression work at the final state with a pressure of 1(MPa) is: 44.32(KJ), (b) Compression work at the final state with a pressure of 500(KPa): 110.37(KJ) and (c) temperaure of the final state in part b: T=151.83(°C).
Explanation:
Remember that the substance is steam so it's water (H2O) and the initial conditions are and
from a saturated water table and the initial conditions we can determine that the state phase is superheated (see Table 1 attached) because the
from the table 1 we get:
. Now we have second conditions as:
so from the same table we can see the state still superheated and we get
, knowing that it's a isobaric process we can find the compression's work as:
so the compressor's work is: 44.32(KJ). (b) Then the piston reaches the stop and there are two processes in this stage, so Process 1 is isobaric and:
and the second process is isochoric:
,now
. Finally to get the temperarure at the final state in part (b) we get:
from table 2 (see attached) we compare
and
at the saturated water table and find the following:
, so we know that the final state phase is a satured mixture and we get the temperature at the final state as:
.
Answer:
Explanation:
Area of crossection, A = 7.80 cm²
Initial magnetic field, B = 0.5 T
Final magnetic field, B' = 3.3 T
Time, t = 1 s
resistance of the coil, R = 1.2 ohm
The induced emf is given by
where, Ф is the rate of change of magnetic flux.
e = 7.80 x 10^-4 x (3.3 - 0.5) / 1
e = 2.184 mV
i = e/R
i = 2.184/1.2
i = 1.82 mA