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Schach [20]
3 years ago
11

Which of the following is a reasonable ground-state electron configuration?A) 1s21p62d2B) 1s22s42p6C) 1s22s22p5D) 1s22s22d6

Chemistry
1 answer:
Semenov [28]3 years ago
4 0

Answer:

  • <u><em>Option C) 1s² 2s² 2p⁵</em></u>

Explanation:

<em>Ground-state</em> is the configuration of the electrons when every electron of the atom occupies the lowest possible energy level.

The rank of energy of the orbitals may be remembered using Aufbau rules, and it is:

1s² < 2s² < 2p⁶ < 3s² < 3p⁶ < 4s² < 3d¹⁰ < 4p⁶ < 5s² < 4d¹⁰ < 5p⁶ < 6s² < 4f¹⁴ < 5d¹⁰ < 6p⁶ < 7s² < 5f¹⁴ < 6d¹⁰ < 7p⁶

Then, to find whether an electron configuration corresponds to a ground-state one, you must check that the previous order is preserved.

<u>Option A). 1s² 1p⁶ 2d²</u>

The orbital 1p does not exist. So this one is discarded.

<u>Option B) 1s² 2s⁴ 2p⁶</u>

The maximum number of electrons in an s orbital is 2, so 2s⁴ is impossible, and this option is discarded.

<u>Option C) 1s² 2s² 2p⁵</u>

This is correct because the orbitals are filled in the correct increasing energy order, without jumping any one.

<u>Option D) 1s² 2s² 2d⁶</u>

Orbital 2d does not exist, so this option is also discarded.

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A. Consider the following neutral electron configurations in which n has a constant value. Which configuration would belong to t
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Answer:

2s2 2p5

Rb < Sr< Sn< Te<I

Explanation:

Electron affinity is the ability of an atom to accept electrons to form negative ions.

Electron affinity is a periodic trend that decreases down the group but increases across the period.

This accounts for the trends observed in the answer. The atom having the electronic configuration, 2s2 2p5 must be a halogen and it exhibits the highest value of electron affinity.

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Read 2 more answers
What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
tatiyna

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

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What mass of hcl in grams is required to react with 0.750 g of al(oh)3?
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