The three properties of electromagnetic waves are; they travel at the speed of light, they include ultraviolet waves, and they can transfer energy through empty space.
<h2>Further Explanation</h2><h3>A wave</h3>
- A wave is a transmission of a disturbance. It involves transmission of energy from one point which is the source to another point.
- Waves may be classified depending on the need for a transmission medium or based on the vibration of particles relative to the direction of wave motion.
- Waves may be either transverse or longitudinal based on the direction of wave motion relative to the vibration of particles
- Additionally waves may be classified as either electromagnetic wave or mechanical based on the need for a transmission medium.
<h3>Electromagnetic waves </h3>
- Electromagnetic waves are types of waves that do not require a material medium for transmission.
- All waves of the electromagnetic spectrum are electromagnetic transverse waves that do not require a material medium for transmission.
- They include; radio waves, microwaves, infrared, visible light, ultra-violet, x-rays, and gamma rays.
- All waves of the electromagnetic spectrum travel with a speed of light, 3.0 x10^8 m/s.
- Additionally, electromagnetic waves possess energy that is given by; E = hf; where h is the plank's constant and f is the frequency.
keywords: Wave, electromagnetic wave, electromagnetic spectrum
<h2>Learn more about: </h2>
Level: High school
Subject: Physics
Topic: Electromagnetic spectrum
Sub-topic: Properties of an electromagnetic waves
Answer:
a) y= 3.5 10³ m, b) t = 64 s
Explanation:
a) For this exercise we use the vertical launch kinematics equation
Stage 1
y₁ = y₀ + v₀ t + ½ a t²
y₁ = 0 + 0 + ½ a₁ t²
Let's calculate
y₁ = ½ 16 10²
y₁ = 800 m
At the end of this stage it has a speed
v₁ = vo + a₁ t₁
v₁ = 0 + 16 10
v₁ = 160 m / s
Stage 2
y₂ = y₁ + v₁ (t-t₀) + ½ a₂ (t-t₀)²
y₂ = 800 + 150 5 + ½ 11 5²
y₂ = 1092.5 m
Speed is
v₂ = v₁ + a₂ t
v₂ = 160 + 11 5
v₂ = 215 m / s
The rocket continues to follow until the speed reaches zero (v₃ = 0)
v₃² = v₂² - 2 g y₃
0 = v₂² - 2g y₃
y₃ = v₂² / 2g
y₃ = 215²/2 9.8
y₃ = 2358.4 m
The total height is
y = y₃ + y₂
y = 2358.4 + 1092.5
y = 3450.9 m
y= 3.5 10³ m
b) Flight time is the time to go up plus the time to go down
Let's look for the time of stage 3
v₃ = v₂ - g t₃
v₃ = 0
t₃ = v₂ / g
t₃ = 215 / 9.8
t₃ = 21.94 s
The time to climb is
= t₁ + t₂ + t₃
t_{s} = 10+ 5+ 21.94
t_{s} = 36.94 s
The time to descend from the maximum height is
y = v₀ t - ½ g t²
When it starts to slow down it's zero
y = - ½ g t_{b}²
t_{b} = √-2y / g
t_{b} = √(- 2 (-3450.9) /9.8)
t_{b} = 26.54 s
Flight time is the rise time plus the descent date
t = t_{s} + t_{b}
t = 36.94 + 26.54
t =63.84 s
t = 64 s
Answer:
I thought "Born Without a Heart" was pretty good.
Hi
Explanation:
Answer: it goes the same speed as the car
Explanation:
Answer:
Part a)

Part b)
Ball thrown downwards =
Ball thrown upwards =
Part c)

Explanation:
Part a)
Since both the balls are projected with same speed in opposite directions
So here the time difference is the time for which the ball projected upward will move up and come back at the same point of projection
Afterwards the motion will be same as the first ball which is projected downwards
so here the time difference is given as



Part b)
Since the displacement in y direction for two balls is same as well as the the initial speed is also same so final speed is also same for both the balls
so it is given as




Part c)
Relative speed of two balls is given as


now the distance between two balls in 0.8 s is given as


