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noname [10]
3 years ago
14

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. If

the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?
Remember to identify all your data, write the equation, and show your work.
Physics
1 answer:
faltersainse [42]3 years ago
4 0

Answer: 60.65 m

Explanation

Use eqation for distance for vertical throw( down)

Vo=12m/s

t=2.5

S=Vot +gt^2/2

S=12*2.5+9.81*2.5^2/2

S=30+30.65

S=60.65m

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Tema [17]
I'd say it was C. but normally it's caused by the movement of electrons and electrons are negative. so I'm not really sure about this one
8 0
4 years ago
Read 2 more answers
aliaa is skating down a ramp. the wheels on her skateboard have diameters of 60 \text{ mm}60 mm60, start text, space, m, m, end
GarryVolchara [31]

The total distance traveled by Aliaa using her skateboard for 20 revolution of the wheels is equal to 3770 millimeters.

<u>Given the following data:</u>

Diameter of skateboard = 60 mm.

Number of revolution = 20 revolutions.

Radius = diameter/2 = 60/2 = 30 mm.

<h3>What is distance?</h3>

Distance can be defined as the amount of ground covered (traveled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.

For one revolution of the wheels, the distance traveled by Aliaa using her skateboard is given by:

Distance = 2πr

Distance = 2 × 3.142 × 30

Distance = 188.5 mm.

Therefore, the total distance traveled by Aliaa using her skateboard for 20 revolution of the wheels is given by:

Distance = 188.5 × 20

Distance = 3770 millimeters.

Read more on distance per revolutions here: brainly.com/question/10989073

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8 0
2 years ago
A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci
JulijaS [17]

Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

P = \frac{dW}{dt}

The work done by the spring is equal to the elastic potential energy stored in the spring.

U = \frac{1}{2}kx^2

The maximum energy stored in the spring is at the amplitude of the oscillation.

U_{max} =\frac{1}{2}kA^2

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)

When the mass reaches the amplitude:

A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi

because cos(π) = 1.

\omega t = \pi/2

Using ω = 2π/T,

\omega t = \pi/2\\\frac{2\pi}{T}t = \pi/2\\t = \frac{T}{4}

4 0
4 years ago
Adam drops a ball from rest from the top floor of a building at the same time Bob throws a ball horizontally from the same locat
guapka [62]

Answer:

Both balls hit the ground at the same time

Explanation:

Adam drops the ball from rest, so the ball just "<em>falls</em>" in vertical direction, being gravity its only acceleration, for cinematic movements we use that:

y(t)=y_{0}+v_{0y}t+\frac{1}{2}gt^{2}

In this case we have that gravity is negative, and as Adam drops the ball, v_{0y}=0

Bob throws the ball horizontally, so the movement will be a <em>parabola</em>, we can divide into horizontal direction, and vertical direction.

But we only need to analize the vertical movement, in wich again the only acceleration is gravity, and compare it with Adam's ball. Again we have that gravity is negative, and as the initial throw is horizontal, v_{0y}=0

Finally, we have that

y(t)=h-\frac{1}{2}gt^{2}

where

h=y_{0}

both for Adam's vertical drop, and for Bob's vertical component of the parabolic throw.

Now, if we put y(t)=0 (the origin of the vertical coordinate), we get for both cases that

h=\frac{1}{2}gt^{2}

where we can clear the value for the time t, of the fall, wich will be the same in both cases.

Hence, both balls hit the ground at the same time.

3 0
3 years ago
Which would take a longer time to warm up, a piece of brass or a piece of marble, given that both
diamong [38]

Answer:

Explanation:

specific heat of marble is 880 J/kg °C

specific heat of brass is 920 J/kg °C

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Q = m s t

t = Q / m s

if Q and m is constant

t is inversely proportional to specific heat .

so rise in temperature will be inversely proportional to specific heat .

lower the specific heat , higher  will be the rise in temperature . Since marble has lower specific heat , rise in temperature in marble will be higher and quicker .

So brass will take longer time to warm up.

7 0
3 years ago
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