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2 years ago

An object is dropped from an airplane and takes 72 seconds to hit the ground. What is the magnitude of its VF Y ?

Physics

1 answer:

Dafna1 [17]2 years ago

3 0

The final vertical velocity of the object is 705.6 m

Explanation:

Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of

$g=9.8 m/s^2$

towards the ground due to gravity.

Therefore, we can use the following suvat equation:

$v=u+at$

where

v is the final vertical velocity

u is the initial vertical velocity

$a=g$ is the acceleration

t is the time

Since the object is dropped,

u = 0

Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:

$v=0+(9.8)(72)=705.6 m/s$

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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