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Yuliya22 [10]
3 years ago
6

An object is dropped from an airplane and takes 72 seconds to hit the ground. What is the magnitude of its VF Y ?

Physics
1 answer:
Dafna1 [17]3 years ago
3 0

The final vertical velocity of the object is 705.6 m

Explanation:

Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of

g=9.8 m/s^2

towards the ground due to gravity.

Therefore, we can use the following suvat equation:

v=u+at

where

v is the final vertical velocity

u is the initial vertical velocity

a=g is the acceleration

t is the time

Since the object is dropped,

u = 0

Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:

v=0+(9.8)(72)=705.6 m/s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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Explanation & answer:

Given:

Fuel consumption, C = 22 L/h

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output power, P  =  55 kW

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Solution:

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