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3 years ago

What is the complete factorization of the polynomial below

Mathematics

2 answers:

zepelin [54]3 years ago

7 0

Answer:

B. (x+4)(x+i)(x-i)

Step-by-step explanation:

Let $P(x)=x^3-4x^2+x-4$

We can factor this polynomial by grouping:

$P(x)=x^2(x-4)+1(x-4)$

We factor further to obtain:

$P(x)=(x^2+1)(x-4)$

$P(x)=(x^2-\sqrt{-1}^2)(x-4)$

We apply difference of two squares to get:

$P(x)=(x-i)(x+i)(x-4)$

Dovator [93]3 years ago

6 0

Answer:

(x+1)(x-1)(x+4)

Step-by-step explanation:

You might be interested in

-3(1 - 8m - 2n ) in standard form

Sergio [31]

=30m-3 is -3(1-8m-2n) written in standard form

7 0

4 years ago

Anisha invested $8,000 in an account that earns 10% interest How much money will she have in 15 years of the interest is compoun

tamaranim1 [39]

Answer:

A = $35,198.32

Step-by-step explanation:

Use the formula to calculate compound interest:

A = P(1 + i)ⁿ

"A" for total amount after the time period

"P" for principal, or starting money

"i" for the interest rate in a compounding period

To calculate "i":

i = r / c

"n" for the number of compounding periods

To calculate "n":

n = tc

So, we can combine the formulas into:

$A = P(1+\frac{r}{c})^{tc}$

"c" is the compounding periods in a year. (quarterly = 4)

We know:

P = 8000

r = 10% / 100 = 0.1

t = 15

c = 4

Substitute the information in the formula.

$A = P(1+\frac{r}{c})^{tc}$

$A = 8000(1+\frac{0.1}{4})^{15*4}$ Solve "i" and "n"

$A = 8000(1+0.025)^{60}$ Solve inside the brackets

$A = 8000(1.025)^{60}$ Do the exponent before multiplying by 8000

A = 35198.318 Exact answer

A ≈ 35198.32 Round to two decimal places for money

Therefore she will have $35,198.32 after 15 years.

5 0

3 years ago

If y=29,find x y=(x+2)(x-2) Please show working

Ainat [17]

Answer:

x=±sqrt (33)

Step-by-step explanation:

y=(x+2)(x-2)

29=x^2-4. x^2=33, x=±sqrt (33)

6 0

3 years ago

Read 2 more answers

Identify the radical expression of 61/4.

boyakko [2]

Hi how u doin boi the answer id 6555555

8 0

4 years ago

Read 2 more answers

Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced

Sati [7]

Answer:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

Step-by-step explanation:

$\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls}$ , $(denoted \:W_1, W_2, \:and\: W_3)$

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

The tree diagram of this event is also attached.

6 0

4 years ago