3 years ago

What is the complete factorization of the polynomial below

Mathematics

2 answers:

zepelin [54]3 years ago

7 0

Answer:

B. (x+4)(x+i)(x-i)

Step-by-step explanation:

Let $P(x)=x^3-4x^2+x-4$

We can factor this polynomial by grouping:

$P(x)=x^2(x-4)+1(x-4)$

We factor further to obtain:

$P(x)=(x^2+1)(x-4)$

$P(x)=(x^2-\sqrt{-1}^2)(x-4)$

We apply difference of two squares to get:

$P(x)=(x-i)(x+i)(x-4)$

Dovator [93]3 years ago

6 0

Answer:

(x+1)(x-1)(x+4)

Step-by-step explanation:

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