Acceleration = (0.2 x g) = 1.96m/sec^2.
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>
<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
<span>Accelerating force = (735 x 0.2) = 147N</span>
<span>From Ohm's law. V = IR. Where R = 2 Ohms. To calculate the induced current I; We need to calculate the electromotive force or voltage, V. From Faraday's law induced EMF = (The rate of change of magnetic flux density x Area)/ (changein time). Or EMF = BA/t. Where B = Bf - Bi. And BA = Bf* A - Bi* A.
Bf = 2.00 and Bi = 0.500 and t = 0.93s and the area, A = 7.1 cm^2 is 0.000071 m^2. 2
So Emf = 2.00 (0.000071) - 0.500(0.000071) /(0.93) = 1.0654 * 10^(-4)/ 0.93 = 1.1415 * 10^(-4).
Substituting into ohms law, we have,
I = (1.1415 * 10^(-4)) / 2 = 0.57075 * 10^(-4)</span>
Answer:
n = 1.56
Explanation:
The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship
n₁ sin θ₁ = n₂ sin θ₂
n1 = n2 / sin θ₁
For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle
Let's use trigonometry to find angle
tan θ = y / x
θ = tan⁻¹ 7.2 / 8.6
θ = 39.94º
n₁ = 1 / sin 39.94
n = 1.56
This is the refractive index of the liquid
-981N would be the reaction force of a person be that stands completely still with a mass of 100 kg.
An opposing force to an action force is referred to as a reaction force. The response force that results from surface engagement and adhesion while sliding is known as friction. Usually, the activities of applied forces result in reaction forces and reaction moments.
As,
F = ma
where, F = force
m = mass of object
a = acceleration due to gravity
Plugging in the values we get,
F = 100kg × 9.81m/s
F = 981 N
Since, reaction force acts opposite to action force so the correct answer is -981N.
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Answer:
AB = DE <CD <BC
Explanation:
This is an exercise in kinetics, the accelerations defined as the change in velocity over the time interval, therefore the accelerations of a vector.
Because the acceleration is a vector, it has two parts, the modulus that the numerical value of the magnitude and the direction, a change in any of them implies the existence of a relationship.
Let's apply these reasoning to our problem.
AB Path
this path is straight and as they indicate that the constant speed the acceleration is zero
DE path
This path is straight and since the velocity is constant the zero steps
BC path
This path is a curve and the velocity modulus is constant, but its directional changes therefore there is an acceleration called centripetal, given by the expression
= v² / r
where r is the radius of the curve and the direction of acceleration is towards the center of the curve
CD path
This path is a curve and it also has centripetal acceleration, as can be seen in the drawing, the radius of the curve is greater than in section BC, therefore the acceleration is less
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In summary lower accelerations are
AB = DE <CD <BC