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Snezhnost [94]
4 years ago
7

Why is there no drag in space?????? Help me please!!! Thanks!!!

Physics
2 answers:
dolphi86 [110]4 years ago
8 0
If there is no fluid, there is no drag. Drag is generated by the difference in velocity between the solid object and the fluid. 
astraxan [27]4 years ago
7 0
It is beacuse of fluid If there is no fluid, there is no drag. Drag is generated by the difference in velocity between the solid object and the fluid. If this statement is correct then how can there be drag in space if there is no air?
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HOW MANY SIGNIFICANT FIGURES ARE THERE IN THE NUMBER 405,000?
Luba_88 [7]

Answer:

Three, but see below.

Explanation:

You can be certain of three, but that may not be true at all. The only way to know for certain is to put it into scientific notation.

4.05 * 10^5 would be three, but other answers are possible. For example

4.050 * 10^5 would have 4.

3 0
3 years ago
6 A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 4 MPa in the boiler and 2
makvit [3.9K]

To solve this problem we will start by differentiating the values in each of the states of matter. Subsequently through the thermodynamic tables we will look for the values related to the entropy, enthalpy and respective specific volumes. Through the relationship of Power defined as the product between mass and enthalpy and mass, specific volume and pressure, we will find the energetic values in the two states investigated. We will start defining the states

State 1

T_1 = 700\°C

P_1 = 4 Mpa

From steam table

h_1 =3906.41 KJ/Kg

s_1 = 7.62 KJ/Kg.K

Now

s_1 = s_2 = 7.62 KJ/Kg.K <em>As 1-2 is isentropic</em>

State 2

P_2 = 20 Kpa

s_2 = 7.62 KJ/Kg \cdot K

From steam table

h_2 = 2513.33 KJ/Kg

PART A) The power produced by turbine is the product between the mass and the enthalpy difference, then

Power = m \times (h_1-h_2)

P = (50)(3906.41 - 2513.33)

P = 69654kW

b) Pump Work

State 3

P_3 = 20 Kpa

\upsilon= 0.001 m^3/kg

The Work done by the pump is

W= m\upsilon \Delta P

W = (50)(0.001)(4000-20)

W = 199kJ

5 0
3 years ago
A ball rolls at 3 meters per second. how much time does it take for the ball to roll 6 meters
natka813 [3]
2 seconds skins b the answer
5 0
3 years ago
Read 2 more answers
Left arm has area 10.0 cm2, right has area 5.00 cm2. 100 g of water isadded to right side. a) Determine the length of the water
Masja [62]

Answer:

0.49  cm

Explanation:

We are given that

A_1=10 cm^2

A_2=5 cm^2

Mass of water,m=100 g

a.\rho_w=1 g/cm^3

Volume,V=\frac{mass}{density}=\frac{100}{1}=100 cm^3

Length of water column in the right arm=L=\frac{V}{A_2}=\frac{100}{5}=20 cm

b.\rho_m=13.6 g/cm^3

In equilibrium condition  

Pressure at point A=Pressure at point B

P+\rho_mg(h+h_2)=P+\rho_wgL

hA_1=h_2A_2

h_2=\frac{hA_1}{A_2}

13.6\times 9.8(h+h(\frac{A_1}{A_2}))=1\times 9.8\times 20

13.6\times h(\frac{A_2+A_1}{A_2})=20

h=\frac{20A_2}{13.6(A_2+A_1)}

h=\frac{20\times 5}{13.6\times (10+5)}=0.49 cm

4 0
4 years ago
Un caballo parte del reposo y alcanza una velocidad de 15m/s en un tiempo de 8s. ¿ Cuál fue su aceleración y que distancia recor
Lemur [1.5K]

Answer: A 120 metros por segundo

Explanation: multiplicas la velocidad por el tiempo

7 0
3 years ago
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