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3 years ago

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Melinda is running in gym class she has 45 minutes and needs to run 6 miles. write and solve the inequality to find the amount o

f time she can spin running each mile

1 answer:

babymother [125]3 years ago

7 0

So first just do 45 divided by 6 (45/6) and you will get your answer

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What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)

timurjin [86]

$Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}
$ $
 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}$ $A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}$ $Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}$

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2 years ago

Find the slope of the line through (-1,1) and (3, -4)

jarptica [38.1K]

Answer:

= -5/4

Step-by-step explanation:

The slope through two points can be found by

m = (y2-y1)/(x2-x1)

= (-4-1)/(3--1)

= (-4-1)/(3+1)

= -5/4

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3 years ago

Solve the system of equations.<br> y=x+2<br> 4x-4y= 1

Tpy6a [65]

Answer:

No solution

Step-by-step explanation:

4x - 4y = 1
4x - 4(x + 2) = 1
4x - 4x - 8 = 1
- 8 = 1

Our end result is -8 = 1. This is not true, so this system of equations have no solution.

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1 year ago

Read 2 more answers

a coffee shop served 24 people before 7:00am. Two-thirds had decaf, and the remaining ordered a specialty coffee. How many custo

Stolb23 [73]

There were 8 customers who ordered specialty coffee. (24/1 x 1/3 = 8)

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3 years ago

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ozzi

Answer:

the answer is 1 2/3 - 1 3/7 ÷ (1/2+ 4/7) = 2/9

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2 years ago