The data below are from a loading increment in a consolidation test. The thickness of the specimen at time t=0 is 25.4 mm. The s
1 answer:
Answer:
given the above data 90% consolidation would be =22.86
Explanation:
For the above to be feasible we need to have the original thickness divided by the total percentage which is 100 then multiplied by the new percentage which is 90% since t is at the origin , i.e t=0.
The Consolidation test: is used when we wish to determine the rate and magnitude of consolidation when it is restrained laterally and loaded axially.
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Answer:
present cost = $302218.15
Explanation:
given data
cost of the work 1st year A1 = $100,000
cost of the work 2nd year A2 = $85,000
cost of the work 3rd year A3 = $70,000
cost of the work 4th year A4 = $55,000
cost of the work 5th year A4 = $40,000
interest rate r = 6% = 0.06
to find out
present worth cost is for the first 5 years
solution
present worth cost will be here as per given equation
present cost = .........................1
here r is rate of interest and A is amount given
put here value we get
present cost =
present cost = $302218.15