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Rasek [7]
3 years ago
9

What are some goals of NYFEA? Select three options.

Engineering
2 answers:
shutvik [7]3 years ago
8 0

Answer:

developing agricultural leaders

encouraging new and young farmers

encouraging small farms

Explanation:

got it correct

Brianna bts
2 years ago
edge let me guess
faltersainse [42]3 years ago
7 0

Answer:

developing agricultural leaders

encouraging new and young farmers

encouraging small farms

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Determine the Thevenin/Norton Equivalent Circuit with respect to the terminalsa,bas shown in the figure. (Here 1A is an independ
melisa1 [442]

Answer:

the the the the the the the

3 0
4 years ago
Consider uniaxial extension of a test specimen. It has gauge length L = 22 cm (the distance between where it is clamped in the t
Katena32 [7]

Answer:

A) 4800.6 N

B) 0.2255 mm/min

C) 8.6792 inches

Explanation:

Given data :

gauge Length = 22 cm = 220 mm

cross section diameter/thickness = 1.8 mm

young's modulus ( E ) = 205 GPa

Ultimate tensile strength ( σu ) = 420MPa

Time = 2 mins

A) what force would fracture the specimen

σU = Ff /A

where A (area) = thickness * width ( unknown )  hence we assume a width of 6.35 mm

Ff = σU × A =  420 * 1.8 * 6.35 = 4800.6 N

B) calculate the strain rate

Ultimate tensile strength ( σU ) = εE

ε = σU / E = 420/205000 = 0.00205

also  ε ​​​​​​ =  ΔL / Li = ( Lf - Li) / Li = (Lf / Li) - 1

 therefore  ε ​​​​​​ + 1 = (Lf / Li) = 1 + 0.00205 = 1.00205

 Li = gauge length = 220 mm

Hence :  Lf = 1.00205 × gauge length =  1.00205 * 220 =  220.451 mm

  strain rate

(Lf - Li) / Time = (0.451) / 2 min = 0.2255 mm/min

C) Elongation in inches prior to fracture

ΔL = ε × Li = 0.451 mm

Lf = 220 mm + 0.451 mm = 220.451 mm =  8.6792 inches

3 0
3 years ago
Calculate the equivalent capacitance of the three series capacitors in Figure 12-1 A) 0.060 uF B) 0.8 uF C) 0.58 uF D) 0.01 uF
Naddik [55]

Answer:

The correct answer is option (A) 0.060 uF

Note: Kindly find an attached image of the complete question below

Sources: The complete question was well researched from Quizlet.

Explanation:

Solution

Given that:

C₁ = 0.1 μF

C₂ =0.22 μF

C₃ = 0.47 μF

In this case, C₁, C₂ and C₃ are in series

Thus,

Their equivalent becomes:

1/Ceq = (1/C₁ + 1/C₂ +1/C₃

1/Ceq =[ (1/0.1 + 1/0.22 +1/0.47)]

1/Ceq =[(0.22 * 0.47) + (0.1 * 0.47) + (0.1 * 0.22)/(0.1 * 0.22 *0.47)]

1/Ceq =[(0.1034 + 0.047 + 0.022)/(0.01034)

1/Ceq =[(0.1724)/(0.01034)]

1/Ceq = [(16.67)]

1/Ceq =(1/16.67) = 0.059μf

Ceq = 0.059μf ≈ 0.060μf

Therefore the equivalent capacitance of the three series capacitors is 0.060μf

4 0
3 years ago
Please solve part two
Burka [1]

Answer:

Wat part 2

Explanation:

7 0
3 years ago
It is not a practical proposition to take direct measurements in nanoscale, but we can estimate variations in position and momen
Volgvan

Answer:

Answer is c Heisenberg's uncertainty principle

Explanation:

According to Heisenberg's uncertainty principle there is always an inherent uncertainty in measuring the position and momentum of a particle simultaneously.

Mathematically

\Delta x\times \Delta \overrightarrow{p}\geq \frac{h}{4\pi }

here 'h' is planck's constant

7 0
3 years ago
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