Answer:
It will lead to overestimation of the percent recovery
Explanation:
The percent recovery refers to the percentage of the pure compound recovered after a chemical process. It is a ratio of the pure compound recovered to the original substance multiplied by 100%.
If the sample was incompletely dried and the recrystallization solvent is still present, the percent recovery will be overestimated and we will have a value that is greater than the accurate percent recovery due to solvent impurities present.
Answer : The partial pressure of
is 102.3 mmHg.
Explanation :
As per question,
Mass of
= 62.9 g
Mass of
= 33.2 g
Molar mass of
= 18 g/mole
Molar mass of
= 62 g/mole
First we have to calculate the moles of
and
.
![\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{62.9g}{18g/mole}=3.49mole](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DH_2O%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DH_2O%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DH_2O%7D%3D%5Cfrac%7B62.9g%7D%7B18g%2Fmole%7D%3D3.49mole)
![\text{Moles of }HOCH_2CH_2OH=\frac{\text{Mass of }HOCH_2CH_2OH}{\text{Molar mass of }HOCH_2CH_2OH}=\frac{33.2g}{62g/mole}=0.536mole](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DHOCH_2CH_2OH%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DHOCH_2CH_2OH%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DHOCH_2CH_2OH%7D%3D%5Cfrac%7B33.2g%7D%7B62g%2Fmole%7D%3D0.536mole)
Now we have to calculate the mole fraction of
and
.
![\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }HOCH_2CH_2OH}=\frac{3.49}{3.49+0.536}=0.867](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20%7DH_2O%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20%7DH_2O%7D%7B%5Ctext%7BMoles%20of%20%7DH_2O%2B%5Ctext%7BMoles%20of%20%7DHOCH_2CH_2OH%7D%3D%5Cfrac%7B3.49%7D%7B3.49%2B0.536%7D%3D0.867)
![\text{Mole fraction of }HOCH_2CH_2OH=\frac{\text{Moles of }HOCH_2CH_2OH}{\text{Moles of }H_2O+\text{Moles of }HOCH_2CH_2OH}=\frac{0.536}{3.49+0.536}=0.134](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20%7DHOCH_2CH_2OH%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20%7DHOCH_2CH_2OH%7D%7B%5Ctext%7BMoles%20of%20%7DH_2O%2B%5Ctext%7BMoles%20of%20%7DHOCH_2CH_2OH%7D%3D%5Cfrac%7B0.536%7D%7B3.49%2B0.536%7D%3D0.134)
Now we have to partial pressure of
.
According to the Raoult's law,
![p^o=X\times p_T](https://tex.z-dn.net/?f=p%5Eo%3DX%5Ctimes%20p_T)
where,
= partial pressure of water vapor
= total pressure of gas
= mole fraction of water vapor
![p_{H_2O}=X_{H_2O}\times p_T](https://tex.z-dn.net/?f=p_%7BH_2O%7D%3DX_%7BH_2O%7D%5Ctimes%20p_T)
![p_{H_2O}=0.867\times 118.0mmHg=102.3mmHg](https://tex.z-dn.net/?f=p_%7BH_2O%7D%3D0.867%5Ctimes%20118.0mmHg%3D102.3mmHg)
Therefore, the partial pressure of
is 102.3 mmHg.
Answer:
the 4s subshell is lower in energy than the 3d subshell
Explanation:
In the element number 24 which is chromium
the electronic configuration should be according to Aufbau principle
will be = ![1s^22s^22p^63s^23p^64s^23d^4](https://tex.z-dn.net/?f=1s%5E22s%5E22p%5E63s%5E23p%5E64s%5E23d%5E4)
but in reality it is = ![1s^22s^22p^63s^23p^64s^13d^5](https://tex.z-dn.net/?f=1s%5E22s%5E22p%5E63s%5E23p%5E64s%5E13d%5E5)
The 6 electrons in the outermost shell will be divided as 5 in 3d subshell and 1 in 4s shell, because half filled orbital
will be more stable than
.
Lipids are hydrophobic; They would be insoluble, group together, and float to the top
Place a burning splint near the opening of a test tube. If a popping noise occurs, it's probably hydrogen. Place a glowing splint in the test tube, and if it reignites, it could be oxygen. Place a burning splint into a test tube, and if it goes out, it could be carbon dioxide.